Skip to main contentSkip to solution

If 3sin⁡θ−4cos⁡θ=03\sin\theta - 4\cos\theta = 0, then value of tan⁡θ⋅csc⁡θ\tan\theta\cdot\csc\theta is :

Solution

✅ Correct Option: 3

3sin⁡θ=4cos⁡θ3\sin\theta=4\cos\theta gives tan⁡θ=43\tan\theta=\frac{4}{3}. So sin⁡θ=45\sin\theta=\frac{4}{5}, cos⁡θ=35\cos\theta=\frac{3}{5}, csc⁡θ=54\csc\theta=\frac{5}{4}. tan⁡θ⋅csc⁡θ=43×54=53\tan\theta\cdot\csc\theta=\frac{4}{3}\times\frac{5}{4}=\frac{5}{3}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question