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If 3sinθ4cosθ=03\sin\theta - 4\cos\theta = 0, then value of tanθcscθ\tan\theta\cdot\csc\theta is :

Solution

Correct Option: 3

3sinθ=4cosθ3\sin\theta=4\cos\theta gives tanθ=43\tan\theta=\frac{4}{3}. So sinθ=45\sin\theta=\frac{4}{5}, cosθ=35\cos\theta=\frac{3}{5}, cscθ=54\csc\theta=\frac{5}{4}. tanθcscθ=43×54=53\tan\theta\cdot\csc\theta=\frac{4}{3}\times\frac{5}{4}=\frac{5}{3}.

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