Quantitative Reasoning

Probability

Medium

What is the probability that any non-leap year will have 53 Sundays?

$\frac{1}{53}$

$\frac{2}{53}$

$\frac{1}{7}$

$\frac{2}{7}$

✅ Correct Option: 3

A non-leap year has 365 days = 52 weeks + 1 extra day.

That extra day can be any of the 7 days of the week with equal probability. For 53 Sundays, the extra day must be Sunday.

P(53 Sundays) = $\frac{1}{7}$ .

2026: 26 May Shift 1

The probability of getting a composite number when a six faced unbiased die is thrown?

2025: 20 May Shift 1

Two persons A and B appear in an interview for two vacancies. If the probabilities of their selections are 1/4 and 1/6 respectively, then the probability that none of them is selected shall be:

2025: 27 May Shift 2

Two dice are thrown simultaneously. What is the probability that 4 will come up on at least one die?

2026: 30 May Shift 2

An unbiased die is rolled. Find the probability of getting a multiple of 2.

2025: 24 May Shift 2

The probability that a card drawn from a pack of 52 cards will be a red card or an ace (including the chance of any red ace), is:

2026: 6 June Shift 1

Two dice are thrown together. What is the probability that the sum of the numbers on the two faces is divisible by 4 or 6?

What is the probability that any non-leap year will have 53 Sundays?

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)