Quantitative Reasoning

Probability

Medium

Four persons are choosen at random from a group of 3 men, 2 women and 4 children. The probability of having 2 children out of 4 is :

$\frac{1}{9}$

$\frac{1}{5}$

$\frac{10}{21}$

$\frac{1}{12}$

✅ Correct Option: 3

Total persons = 9. Choose 4 from 9: $\binom{9}{4}=126$ .

Favorable: 2 children from 4 and 2 others from 5: $\binom{4}{2}\binom{5}{2}=6 \times 10=60$ .

Probability = $\frac{60}{126}=\frac{10}{21}$ .

2025: 22 May Shift 1

Two unbiased coins are tossed. The probability of getting at least one head is:

2026: 20 May Shift 1

The probability that a card drawn from a pack of 52 cards will be a spade or a queen, is

2026: 19 May Shift 1

A box contains 3 blue, 2 white, and 5 red balls. If a ball is drawn at random from the box, what is the probability that it will be red?

2026: 14 May Shift 1

If A and B are two disjoint events then

A. A ∩ B = Φ

B. P ( A ∩ B ) = 0

C. P ( A ∪ B ) = P (A) + P (B)

D. P ( A ∩ B ) = 1

Choose the correct answer from the options given below:

2023: 15 June Shift 2

If $P(E) = 0.05$ , what is the probability of 'not E'?

2026: 14 May Shift 2

The probability of getting an odd number when you roll a die, is:

Solution