If (x+y) : (x-y) = 7 : 3, then find the ratio of (x^2+y^2) : (x^2-y^2). Option 1: 21 : 29 Option 2: 29 : 21 Option 3: 3 : 4 Option 4: 4 : 3

Answer: 29 : 21. Solution: (x+y)/(x-y)=7/3 gives 3x+3y=7x-7y, so 4x=10y, x/y=5/2. Let x=5, y=2. Then x^2+y^2=29, x^2-y^2=21. Ratio =29:21.

Arithmetic

Ratio, Proportion & Variation

Medium

If $(x+y) : (x-y) = 7 : 3$ , then find the ratio of $(x^2+y^2) : (x^2-y^2)$ .

21 : 29

29 : 21

3 : 4

4 : 3

✅ Correct Option: 2

$\frac{x+y}{x-y}=\frac{7}{3}$ gives $3x+3y=7x-7y$ , so $4x=10y$ , $\frac{x}{y}=\frac{5}{2}$ . Let $x=5$ , $y=2$ . Then $x^2+y^2=29$ , $x^2-y^2=21$ . Ratio $=29:21$ .

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If (x+y):(x−y)=7:3(x+y) : (x-y) = 7 : 3(x+y):(x−y)=7:3, then find the ratio of (x2+y2):(x2−y2)(x^2+y^2) : (x^2-y^2)(x2+y2):(x2−y2).

Solution

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CUET General Test Past Year Questions (Topic-Wise)

If $(x+y) : (x-y) = 7 : 3$ , then find the ratio of $(x^2+y^2) : (x^2-y^2)$ .