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Tickets numbered from 1 to 20 are mixed and a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?

Solution

Correct Option: 1

Multiples of 3 between 1 and 20: 3, 6, 9, 12, 15, 18, i.e., 6 favourable outcomes out of 20.

Probability =620=310= \frac{6}{20} = \frac{3}{10}.

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