Arithmetic

Central Tendency

Medium

Thirty six students of class IX contributed on an average Rs 42 towards flood relief fund whereas some students of class X contributed on an average Rs 54.50. If the overall average contribution per student remained Rs 47, then how many students of class X contributed ?

✅ Correct Option: 3

Let $x$ = students of class X. Total contribution: $36\times 42 + x\times 54.50 = (36+x)\times 47$ . So $1512+54.5x = 1692+47x$ . Then $7.5x=180$ , giving $x=24$ .

2025: 19 May Shift 1

If the data is not following a symmetrical distribution, then the relationship between mean, median and mode is:

2022: 24 Aug Shift 1

If the mean of $x-3$ , $x+4$ , $2x-1$ , $x+3$ is 2. The value of x is :

2022: 26 Aug Shift 1

The average of the four consecutive odd number is 16. What is the difference between third and first number?

2025: 13 May Shift 1

The marks out of 50 obtained by 100 students in a test are given below as:

Marks obtained	20	25	28	29	33	38	42	43
Number of students	6	20	24	28	15	4	2	1

Find the value of the (3 mode - 2 median).

2026: 19 May Shift 1

The median of class frequency distribution is:

Class:	0 - 25	25 - 50	50 - 75	75 - 100	Total
Frequency:	25	32	15	16	88

2022: 6 Aug Shift 1

Median of the data is:

Thirty six students of class IX contributed on an average Rs 42 towards flood relief fund whereas some students of class X contributed on an average Rs 54.50. If the overall average contribution per student remained Rs 47, then how many students of class X contributed ?

Solution

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