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A and B working together can do a work in 10 days. If A can do the work in 15 days, then how many days will B take to do the same work?

Solution

Correct Option: 2

Let total work =LCM(10,15)=30= \text{LCM}(10, 15) = 30 units. Efficiency of A+B =30/10=3= 30/10 = 3; of A =30/15=2= 30/15 = 2. So B =32=1= 3 - 2 = 1. B alone takes 30/1=3030/1 = 30 days.

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