Arithmetic

Central Tendency

Medium

The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.

85.52

79.35

✅ Correct Option: 3

Initial sum $= 79.5 \times 50 = 3975$ . Correct sum $= 3975 - 94 - 69 + 49 + 89 = 3950$ . Correct mean $= 3950/50 = 79$ .

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The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.

Solution

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