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Match List - I with List - II.

List - IList - II
(1) 14110(x+3)=56x14 - \frac{1}{10}(x+3) = \frac{5}{6}x(I) 4
(2) (x5)2(x+3)2=48(x-5)^2 - (x+3)^2 = 48(II) 232-\frac{23}{2}
(3) 6(x4)=4(x3)(3x8)6(x-4) = 4(x-3) - (3x-8)(III) 61
(4) (2x1)(2x+3)=(2x7)(2x+7)(2x-1)(2x+3) = (2x-7)(2x+7)(IV) 2-2

Choose the correct answer from the options given below:

Solution

Correct Option: 3

Eq (3): 6(x4)=4(x3)(3x8)6x24=x4x=46(x-4) = 4(x-3) - (3x-8) \Rightarrow 6x-24 = x - 4 \Rightarrow x = 4 (I). Eq (2): (x5)2(x+3)2=16x+16=48x=2(x-5)^2 - (x+3)^2 = -16x + 16 = 48 \Rightarrow x = -2 (IV). Eq (4): 4x2+4x3=4x249x=23/24x^2+4x-3 = 4x^2 - 49 \Rightarrow x = -23/2 (II). Eq (1) therefore maps to III (61). Match: (1)-(III), (2)-(IV), (3)-(I), (4)-(II).

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