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For which value of the k, the pair of linear equations has no solution

6x3y+10=06x - 3y + 10 = 0 and kxy+9=0kx - y + 9 = 0 :

Solution

Correct Option: 3

For no solution: a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}.

6k=31=3\frac{6}{k} = \frac{-3}{-1} = 3

k=63=2k = \frac{6}{3} = 2.

Check: 1093\frac{10}{9} \neq 3, so no solution holds.

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