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A, B, C, are three points on the circumference of a circle and if AB=AC=52AB = AC = 5\sqrt{2}, angle BAC=90BAC = 90 degrees then radius of the circle is __________.

Solution

Correct Option: 2

Since angle BAC = 90 degrees and inscribed in a circle, BC is a diameter.

BC = AB2+AC2=50+50=100=10\sqrt{AB^2 + AC^2} = \sqrt{50 + 50} = \sqrt{100} = 10.

Radius = 102=5\frac{10}{2} = 5 cm.

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