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In a 2-digit number, the ten's digit is two times its unit's digit and the number is 12 less than two times the number obtained by interchanging its digits. Find the original number.

Solution

Correct Option: 3

Let unit digit =u= u, ten's digit =2u= 2u. Original number =10(2u)+u=21u= 10(2u) + u = 21u. Interchanged number =10u+2u=12u= 10u + 2u = 12u. Given: 21u=2(12u)1221u = 2(12u) - 12, so 21u=24u1221u = 24u - 12, giving u=4u = 4. Ten's digit =8= 8, so number is 8484.

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