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'A' spins a spinner that is split into 10 equal sections marked as 1, 3, 2, 1, 2, 2, 3, 1, 2, 1. What is the probability that the spinner will land on number 2 ?

Solution

Correct Option: 2

Count of 2s in the list 1,3,2,1,2,2,3,1,2,1: positions 3, 5, 6, 9 give four 2s.

Probability = 410=25\frac{4}{10} = \frac{2}{5}.

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