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Which of the following pair of linear equations has no solution?

(A) 2x+3y−1=02x + 3y - 1 = 0 and 4x+6y−4=04x + 6y - 4 = 0

(B) x−2y=0x - 2y = 0 and 3x+4y−20=03x + 4y - 20 = 0

(C) x+2y−3=0x + 2y - 3 = 0 and 5x+10y+7=05x + 10y + 7 = 0

(D) x+2y−4=0x + 2y - 4 = 0 and 2x+4y−12=02x + 4y - 12 = 0

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

No solution requires a1a2=b1b2≠c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}. In (A) 12=12≠14\frac12=\frac12\neq\frac14, in (C) 15=15≠−37\frac15=\frac15\neq-\frac37, in (D) 12=12≠13\frac12=\frac12\neq\frac13, so all three are parallel. In (B) 13≠−12\frac13\neq-\frac12, giving a unique solution. Answer: (A), (C) and (D).

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