Skip to main contentSkip to solution

Read the information given below carefully and answer the question that follows:

Aditi, a salesgirl is appointed at a basic salary of ₹ 1200 per month. The condition of employment further stated that for every sale of ₹ 10000 or above she does, she will get 50 % of basic salary and 10 % of the sales as special incentive. However, this incentive scheme shall not work on the first ₹ 10000 of sales made. What should be the value of sales if Aditi wants to earn ₹ 7600 in a particular month?

Solution

✅ Correct Option: 3

Aditi's salary structure:

Basic Salary =₹1200= ₹1200 (fixed, always paid)

If total sales are ₹10,000₹10,000 or more, she additionally gets:

  • Bonus =50%= 50\% of basic salary =0.5×1200=₹600= 0.5 \times 1200 = ₹600
  • Commission =10%= 10\% of sales above ₹10,000₹10,000

The first ₹10,000₹10,000 of sales earns no bonus and no commission.


Aditi wants to earn ₹7600₹7600 in total.

Since ₹7600₹7600 is much more than just the basic salary of ₹1200₹1200, she must be getting the special incentive. This means her sales must be at least ₹10,000₹10,000.

Let total sales =S= S

Since S≥₹10,000S \geq ₹10,000:

Total Earning == Basic Salary ++ Bonus ++ Commission

Total Earning 1200+600×(S−10000)10000+0.1×(S−10000)=76001200+600\times\frac{(S-10000)}{10000}+0.1\times(S-10000)=7600


To make this easier, let's substitute X=S−10000X = S - 10000 since this expression appears twice.

The equation becomes:

1200+600×X10000+0.1×X=76001200 + 600 \times \frac{X}{10000} + 0.1 \times X = 7600


Simplify the fraction 600X10000\frac{600X}{10000}:

600X10000=6X100=0.06X\frac{600X}{10000} = \frac{6X}{100} = 0.06X

So our equation is now:

1200+0.06X+0.1X=76001200 + 0.06X + 0.1X = 7600


Combine the XX terms:

0.06X+0.1X=0.16X0.06X + 0.1X = 0.16X

This gives us:

1200+0.16X=76001200 + 0.16X = 7600


Subtract 12001200 from both sides:

0.16X=7600−12000.16X = 7600 - 1200

0.16X=64000.16X = 6400


Divide both sides by 0.160.16:

X=64000.16X = \frac{6400}{0.16}

X=40000X = 40000


Recall that X=S−10000X = S - 10000, so:

S−10000=40000S - 10000 = 40000

S=40000+10000S = 40000 + 10000

S=50000S = 50000


Verify by substituting S=50000S = 50000 back into the original equation:

1200+600×4000010000+0.1×400001200 + 600 \times \frac{40000}{10000} + 0.1 \times 40000

=1200+600×4+4000= 1200 + 600 \times 4 + 4000

=1200+2400+4000= 1200 + 2400 + 4000

=7600= 7600 ✓

Final Answer: S=50000S = 50000


Therefore, Aditi needs to make sales worth ₹50,000₹50,000 to earn ₹7600₹7600 in that month.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question