Find the angle of elevation of the Sun, when the length of the shadow of a tree is 1/√3 times the height of the tree. Option 1: 30° Option 2: 45° Option 3: 60° Option 4: 90°

Answer: 60°. Solution: Let height of tree = h, shadow length = h/√3. = (height)/(shadow) = h/(h/√3) = √3 Therefore, = 60°.

Geometry

Trigonometry

Easy

Find the angle of elevation of the Sun, when the length of the shadow of a tree is $\frac{1}{\sqrt{3}}$ times the height of the tree.

30°

45°

60°

90°

✅ Correct Option: 3

Let height of tree = h, shadow length = $\frac{h}{\sqrt{3}}$ .

$\tan\theta = \frac{\text{height}}{\text{shadow}} = \frac{h}{h/\sqrt{3}} = \sqrt{3}$

Therefore, $\theta = 60°$ .

2026: 12 May Shift 2

The angle of elevation of the sun, when the length of the shadow of a tree is √3 times the height of the tree, is:

2025: 22 May Shift 1

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2025: 30 May Shift 2

From the top of a tower, the angles of depression of two objects A and B (situated on the ground on the same side of the tower) are observed to be 30° and 60°, respectively. If the distance between the objects is 200√3 m, then the height of the tower is?

2025: 2 June Shift 2

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2026: 25 May Shift 2

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2026: 18 May Shift 1

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Solution

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Find the angle of elevation of the Sun, when the length of the shadow of a tree is $\frac{1}{\sqrt{3}}$ times the height of the tree.