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In a row of 40 children, A is 13th from the left end and B is ninth from the right end. How many children are there between A and C if C is forth to the left of B.

Solution

Correct Option: 2

A's position from left = 13.

B's position from left = 40 - 9 + 1 = 32.

C is 4th to the left of B, so C's position = 32 - 4 = 28.

Number of children between A (position 13) and C (position 28) = 28 - 13 - 1 = 14.

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