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If the height of a pole is 838\sqrt{3} meters and the length of its shadow is 8 meters, then the angle of elevation of the sun is:

Solution

✅ Correct Option: 3

A pole of height 838\sqrt{3} meters casts a shadow of length 8 meters. This creates a right triangle where:

  • The pole is the vertical side (opposite) = 838\sqrt{3} meters
  • The shadow is the horizontal side (adjacent) = 88 meters
  • The angle between the ground and the sun's ray is θ\theta

Since we know the opposite and adjacent sides, we use the tangent ratio:

tan⁡(θ)=OppositeAdjacent=Height of poleLength of shadow\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{\text{Height of pole}}{\text{Length of shadow}}

Substituting the values:

tan⁡(θ)=838\tan(\theta) = \frac{8\sqrt{3}}{8}

Simplifying:

tan⁡(θ)=3\tan(\theta) = \sqrt{3}


From standard trigonometric values:

  • tan⁡(30°)=13\tan(30°) = \frac{1}{\sqrt{3}}
  • tan⁡(45°)=1\tan(45°) = 1
  • tan⁡(60°)=3\tan(60°) = \sqrt{3}

Since tan⁡(θ)=3\tan(\theta) = \sqrt{3}:

θ=60°\theta = 60°


Therefore, the angle of elevation of the sun is 60°60°.

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