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The angle of elevation from a point situated at a distance of 70 meter from the base of a tower is 60060^0. The height of the tower is:

Solution

✅ Correct Option: 3

In the right triangle formed by the tower and the ground, tan⁡60°=h70\tan 60° = \dfrac{h}{70}.

Since tan⁡60°=3\tan 60° = \sqrt{3}, we get h=703h = 70\sqrt{3} metres.

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