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Solution

Correct Option: 4

First term a = 3, common difference d = 4, last term ana_n = 407.

an=a+(n1)da_n = a + (n-1)d

407=3+(n1)×4407 = 3 + (n-1) \times 4

(n1)×4=404(n-1) \times 4 = 404

n1=101n - 1 = 101, so n = 102.

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