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If Δ\Delta stands for the operation on adding first number to the twice of the second number. Then, find the value of (2 Δ 3) Δ 4(2\ \Delta\ 3)\ \Delta\ 4.

Solution

Correct Option: 4

Operation: aΔb=a+2ba\Delta b=a+2b. 2Δ3=2+6=82\Delta3=2+6=8. Then 8Δ4=8+8=168\Delta4=8+8=16.

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