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Find the A.P. whose 3rd term is 18 and 12th term is 72.

Solution

Correct Option: 1

Using an=a+(n1)da_n = a + (n - 1)d: a+2d=18a + 2d = 18 and a+11d=72a + 11d = 72. Subtracting: 9d=54d=69d = 54 \Rightarrow d = 6.

Then a=1812=6a = 18 - 12 = 6. AP: 6, 12, 18, ...

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