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The altitude drown to the base of an isosceles triangle is 16 cm and it's perimeter is 64 cm what is the area of triangle?

Solution

Correct Option: 4

Let equal sides aa, base bb. Perimeter: 2a+b=642a+b=64. Altitude bisects base, so a2=162+(b/2)2a^2=16^2+(b/2)^2. Substituting a=32b/2a=32-b/2 gives 102432b+b2/4=256+b2/41024-32b+b^2/4=256+b^2/4, so b=24b=24. Area =12×24×16=192=\frac{1}{2}\times24\times16=192 cm2^2.

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