Skip to main contentSkip to solution

Let A be the greatest number that will divide 505, 555 and 605, leaving the same remainder in each case. Then sum of the digits in a is:

Solution

Correct Option: 2

Required number == HCF of successive differences == HCF(555505,605555,605505)=(555-505, 605-555, 605-505)= HCF(50,50,100)=50(50,50,100)=50. Sum of digits of 50 =5+0=5=5+0=5.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question