Find the area of an equilateral triangle each of whose sides measures 4 cm: Option 1: 4√3 cm^2 Option 2: 4√3 m^2 Option 3: 3√3 cm^2 Option 4: 3√3 m^2

Answer: 4√3 cm^2. Solution: Area of equilateral triangle = √3/4 x (side)^2 = √3/4 x 4^2 = √3/4 x 16 = 4√3 cm^2.

Geometry

Triangles

Easy

Find the area of an equilateral triangle each of whose sides measures 4 cm:

$4\sqrt{3}$ $cm^2$

$4\sqrt{3}$ $m^2$

$3\sqrt{3}$ $cm^2$

$3\sqrt{3}$ $m^2$

✅ Correct Option: 1

Area of equilateral triangle = $\frac{\sqrt{3}}{4} \times (\text{side})^2 = \frac{\sqrt{3}}{4} \times 4^2 = \frac{\sqrt{3}}{4} \times 16 = 4\sqrt{3}$ $\text{cm}^2$ .

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In triangle $ABC$ , points $D$ and $E$ are on $AB$ and $AC$ respectively such that $DE$ is parallel to $BC$ . If $AD = 6$ cm, $DB = 4$ cm, $AE = 9$ cm, then the length of $EC$ (in cm) is:

Find the area of an equilateral triangle each of whose sides measures 4 cm:

Solution

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