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Find the area of a triangle formed by the points A(6, 2), B(4, 7) and C(7, -4)

Solution

✅ Correct Option: 3

Area =12∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣= \dfrac{1}{2}|x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)|

=12∣6(7+4)+4(−4−2)+7(2−7)∣= \dfrac{1}{2}|6(7+4) + 4(-4-2) + 7(2-7)|

=12∣66−24−35∣=72=3.5= \dfrac{1}{2}|66 - 24 - 35| = \dfrac{7}{2} = 3.5 sq units.

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