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A fast train takes 3 hours less than a slow train for a journey of 600 km. If the speed of the fast train 10 km/hr higher than that of slow train, then find the speed of the slow train.

Solution

✅ Correct Option: 2

Let the slow speed be xx. Then 600x−600x+10=3\frac{600}{x} - \frac{600}{x+10} = 3.

This gives 6000=3x(x+10)6000 = 3x(x+10), so x2+10x−2000=0x^2 + 10x - 2000 = 0.

Factoring, (x+50)(x−40)=0(x+50)(x-40) = 0, and taking the positive root, x=40x = 40 km/hr.

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