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A tyre has two punctures. The first puncture alone would have made the tyre flat in 6 minutes and the second alone would have done it in 9 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat?

Solution

Correct Option: 1

Combined rate =16+19=3+218=518= \frac{1}{6} + \frac{1}{9} = \frac{3 + 2}{18} = \frac{5}{18}. Time =185=335= \frac{18}{5} = 3\frac{3}{5} minutes.

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