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The value of (793+232)2(793232)2(793×232)\frac{(793 + 232)^2 - (793 - 232)^2}{(793 \times 232)} is

Solution

Correct Option: 2

Using identity (a+b)2(ab)2=4ab(a+b)^2 - (a-b)^2 = 4ab. So numerator =4×793×232= 4 \times 793 \times 232. Dividing by 793×232793 \times 232 gives 4.

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