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If x3=2y\sqrt[3]{x} = 2y. Then, the value of y3x\frac{y^3}{x} is ______

Solution

Correct Option: 3

Cubing both sides: x=8y3x = 8y^3. So y3x=y38y3=18\frac{y^3}{x} = \frac{y^3}{8y^3} = \frac{1}{8}.

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