If principal = P, Rate R = R% per annum, T = Time year, SI = Simple interest, then

a. $T = \frac{100 \times SI}{P \times R}$

b. $SI = \frac{P \times R \times T}{100}$

c. $R = \frac{P \times SI \times T}{100}$

d. $T = \frac{P \times SI \times T}{100}$

e. $R = \frac{100 \times SI}{P \times T}$

In what time will the simple interest on ₹2200 at 6% per annum be the same as that on ₹1650 at 9% per annum in 10 years?

Consider the compound interest of the following

(A) The compound interest on Rs 16000 at 20% per annum for 9 months, compounded quarterly is: Rs 2522

(B) The compound interest on Rs 2800 at 10% per annum for 18 months, compounded annually is: Rs 434

Choose the correct statement(s):

The difference between the amounts of compound interest and simple interest on the same amount invested at the same rate for 2 years in Rs. 32. If the interest rate is 4% per annum, calculate the amount invested.(in Rs.)

Find a simple interest on ₹ 7200 for 7 years at a rate of 14% per annum.

A sum of Rs. 1500 is invested at 5% p.a. simple interest. If the interest is added to the principal after every 10 years, the amount will become Rs. 3000 after :

The simple interest of an amount is $\frac{16}{25}$ of the principal. Find the rate % PA, if the time and rate both are numerically equal.