JIPMAT 2024Geometry > Hard012\frac{1}{2}2112\sqrt{2}2✅ Correct Option: 2Related questions:The minimum value of (2sin2θ+3cos2θ)(2 \sin^2\theta + 3 \cos^2\theta)(2sin2θ+3cos2θ) isTwo poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their foot is 12 m, then the distance between their tops isGiven below are two statements: Statement I: cot30∘+1cot30∘−1=2(cos30∘+1)\frac{\cot 30^{\circ}+1}{\cot 30^{\circ}-1}=2\left(\cos 30^{\circ}+1\right)cot30∘−1cot30∘+1=2(cos30∘+1) Statement II : 2sin45∘cos45∘−tan45∘cot45∘=02 \sin 45^{\circ} \cos 45^{\circ}-\tan 45^{\circ} \cot 45^{\circ}=02sin45∘cos45∘−tan45∘cot45∘=0