JIPMAT 2021Algebra > Conceptual15\frac{1}{5}51015✅ Correct Option: 4Related questions:JIPMAT 2023Assertion [A]: Sum of the first hundred even natural numbers divisible by 5 is 45050. Reason (R): Sum of the first n-terms of an Arithmetic Progression is given by S=(n/2)∗(a+l)S = (n/2) *(a + l)S=(n/2)∗(a+l) where a=first term, l=last term. Choose the correct answer from the options given below.JIPMAT 2021If the mthm^{\text{th}}mth term of an arithmetic progression is 1n\frac{1}{n}n1 and the nthn^{\text{th}}nth term is 1m\frac{1}{m}m1, then the mnthmn^{\text{th}}mnth term of this progression will beJIPMAT 2022The sum of n−n-n− terms of sequence 11×2+12×3+13×4……\frac{1}{1 \times 2}+\frac{1}{2 \times 3}+\frac{1}{3 \times 4} \ldots \ldots1×21+2×31+3×41……. Is