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ABC is right angled triangle at C. Let BC = a, CA = b and AB = c and let p be the length of perpendicular from C on AB, then cp is equal to

Solution

✅ Correct Option: 2
  1. In right triangle ABC:
  • BC = aa
    • CA = bb
    • AB = cc
    • Perpendicular from C to AB = pp
  1. Area of triangle can be written in two ways:
  • Area = 12×base×height\frac{1}{2} × \text{base} × \text{height}
    • Area = 12×product of sides containing right angle\frac{1}{2} × \text{product of sides containing right angle}
  1. Using both formulas:

12c×p=12a×b\frac{1}{2}c × p = \frac{1}{2}a × b

  1. Therefore:

cp=abcp = ab

The answer is abab.

The key here is that the area of a right triangle equals half the product of either:

  • Base and height (cp/2cp/2)
  • Two sides forming right angle (ab/2ab/2)

Since these are equal, cp=abcp = ab

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