Match List – I and List- II and choose the correct answer from the options given below. Option 1: A]- (IV), B]- (III), C]- (I), D]- (II) Option 2: A]- (I), B]- (II), C]- (III), D]- (IV) Option 3: A]- (II), B]- (I), C]- (III), D]– (IV) Option 4: A]- (III), B]- (IV), C]- (I), D]- (II)

Answer: A]- (IV), B]- (III), C]- (I), D]- (II). Solution: Absolute angle between hands of a clock is:, 30H - 11/2M, where H is hours (1-12) and M is minutes (0-59) Let's solve for each time: 1. 7:15, 30(7) - 11/2(15), 210 - 82.5, = 127.5° → matches C 2. 9:15, 30(9) - 11/2(15), 270 - 82.5, = 187.5° → matches D 3. 4:30, 30(4) - 11/2(30), 120 - 165, = 45° → matches B 4. 2:30, 30(2) - 11/2(30), 60 - 165, = 105° → matches A Therefore: (I) 7:15 pairs with C. 127.5° (II) 9:15 pairs with D. 187.5° (III) 4:30 pairs with B. 45° (IV) 2:30 pairs with A. 105°

Logical Reasoning

Clocks & Calendar

Easy

Angle between hour hand and minute hand	Time
A. 105°	(I) 7:15
B. 45°	(II) 9:15
C. 127.5°	(III) 4:30
D. 187.5°	(IV) 2:30

Match List – I and List- II and choose the correct answer from the options given below.

A]- (IV), B]- (III), C]- (I), D]- (II)

A]- (I), B]- (II), C]- (III), D]- (IV)

A]- (II), B]- (I), C]- (III), D]– (IV)

A]- (III), B]- (IV), C]- (I), D]- (II)

✅ Correct Option: 1

Absolute angle between hands of a clock is:

$|30H - \frac{11}{2}M|$ , where H is hours (1-12) and M is minutes (0-59)

Let's solve for each time:

7:15

$|30(7) - \frac{11}{2}(15)|$

$|210 - 82.5|$

$= 127.5°$ → matches C

9:15

$|30(9) - \frac{11}{2}(15)|$

$|270 - 82.5|$

$= 187.5°$ → matches D

4:30

$|30(4) - \frac{11}{2}(30)|$

$|120 - 165|$

$= 45°$ → matches B

2:30

$|30(2) - \frac{11}{2}(30)|$

$|60 - 165|$

$= 105°$ → matches A

Therefore:

(I) 7:15 pairs with C. 127.5°

(II) 9:15 pairs with D. 187.5°

(III) 4:30 pairs with B. 45°

(IV) 2:30 pairs with A. 105°

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Solution

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