A watch which gains uniformly is 2 minutes slow at 10 AM on Wednesday and 2 1/2 minutes fast at 1 PM the following day. When will it show the correct time ? Option 1: 10: 30 AM, Thursday Option 2: 9: 15 PM, Wednesday Option 3: 10: 30 AM, Wednesday Option 4: 10 : 00 PM, Wednesday

Answer: 10 : 00 PM, Wednesday. Solution: At 10 AM on Wednesday, watch is 2 minutes slow At 1 PM next day (27 hours later), watch is 2.5 minutes fast Total time elapsed = 27 hours Total change in watch = 2 + 2.5 = 4.5 minutes gained Rate of gain = 4.5/27 minutes per hour = 1/6 minutes per hour Time when watch shows correct time: Initial error = -2 minutes (slow) To correct this at rate of 1/6 minutes per hour: Time needed = 2 1/6 = 12 hours Therefore, watch will show correct time 12 hours after 10 AM Wednesday This is 10 PM Wednesday

Logical Reasoning

Clocks & Calendar

Medium

A watch which gains uniformly is 2 minutes slow at $10 \mathrm{AM}$ on Wednesday and $2 \frac{1}{2}$ minutes fast at 1 PM the following day. When will it show the correct time ?

$10: 30$ AM, Thursday

$9: 15$ PM, Wednesday

$10: 30$ AM, Wednesday

$10 : 00$ PM, Wednesday

✅ Correct Option: 4

At 10 AM on Wednesday, watch is 2 minutes slow

At 1 PM next day (27 hours later), watch is 2.5 minutes fast

Total time elapsed = 27 hours

Total change in watch = 2 + 2.5 = 4.5 minutes gained

Rate of gain = $\frac{4.5}{27}$ minutes per hour = $\frac{1}{6}$ minutes per hour

Time when watch shows correct time:

Initial error = -2 minutes (slow)

To correct this at rate of $\frac{1}{6}$ minutes per hour:

Time needed = $2 \div \frac{1}{6} = 12$ hours

Therefore, watch will show correct time 12 hours after 10 AM Wednesday

This is 10 PM Wednesday

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Solution

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JIPMAT Past Year Questions (Topic-Wise)

A watch which gains uniformly is 2 minutes slow at $10 \mathrm{AM}$ on Wednesday and $2 \frac{1}{2}$ minutes fast at 1 PM the following day. When will it show the correct time ?