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List IList IIA. Mean of first five prime numbers isI. 12B. Mean of all factors of 24 isII. 7.5C. Mean of first six multiples of 4 isIII. 5.6D. If the mean of x−5y,x−3y,x−y,x+y,x+3y and x+5y is 12, then x isIV. 14\begin{array}{|c|c|c|} \hline \textbf{List I} & \textbf{List II} \\ \hline \text{A. Mean of first five prime numbers is} & \text{I. 12} \\ \hline \text{B. Mean of all factors of 24 is} & \text{II. 7.5} \\ \hline \text{C. Mean of first six multiples of 4 is} & \text{III. 5.6} \\ \hline \text{D. If the mean of } x - 5y, x - 3y, x - y, \\x + y, x + 3y \text{ and } x + 5y \text{ is 12, then } x \text{ is} & \text{IV. 14} \\ \hline \end{array}

Match List I with List II. Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Let's solve each case:

A) First five prime numbers: 2, 3, 5, 7, 11

Mean = 2+3+5+7+115=285=5.6\frac{2+3+5+7+11}{5} = \frac{28}{5} = 5.6 (matches III)

B) Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

Mean = 1+2+3+4+6+8+12+248=608=7.5\frac{1+2+3+4+6+8+12+24}{8} = \frac{60}{8} = 7.5 (matches II)

C) First six multiples of 4: 4, 8, 12, 16, 20, 24

Mean = 4+8+12+16+20+246=846=14\frac{4+8+12+16+20+24}{6} = \frac{84}{6} = 14 (matches IV)

D) Mean = 12 for expressions:

x−5y,x−3y,x−y,x+y,x+3y,x+5yx-5y, x-3y, x-y, x+y, x+3y, x+5y

Sum = 6x6x (y terms cancel)

6x6=12\frac{6x}{6} = 12

Therefore x=12x = 12 (matches I)

Hence, Option 2 is the answer.

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