IPMAT IndoreAlgebra > Hardpositive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2}, +\infty)∈(25+57,+∞)negative and monotonically decreasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)negative and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and positive and monotonically increasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)positive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and negative and monotonically decreasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)✅ Correct Option: 3Related questions:IPMAT Indore 2022If f(x2+f(y))=xf(x)+yf\left(x^{2}+f(y)\right)=x f(x)+yf(x2+f(y))=xf(x)+y for all non-negative integers xxx and yyy, then the value of [f(0)]2+f(0)[f(0)]^{2}+f(0)[f(0)]2+f(0) equals _________.IPMAT Indore 2023If f(1)=1f(1) = 1f(1)=1 and f(n)=3n−f(n−1)f(n) = 3n - f(n - 1)f(n)=3n−f(n−1) for all integers n>1n > 1n>1 , then the value of f(2023)f(2023)f(2023) isIPMAT Indore 2024Let fff and ggg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x||f(x)=∣x+∣x∣∣ and g(x)=1xg(x) = \frac{1}{x}g(x)=x1 for x≠0x \neq 0x=0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6}f(a)+g(f(a))=613 for some real aaa, then the maximum possible value off(g(a)) f(g(a))f(g(a)) is: