IPMAT IndoreAlgebra > Hardpositive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2}, +\infty)∈(25+57,+∞)negative and monotonically decreasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)negative and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and positive and monotonically increasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)positive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and negative and monotonically decreasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)✅ Correct Option: 3Related questions:IPMAT Indore 2021If a function f(a)=max(a,0)f(a) = max (a, 0)f(a)=max(a,0) then the smallest integer value of xxx for which the equation f(x−3)+2f(x+1)=8f(x - 3) + 2f(x + 1) = 8f(x−3)+2f(x+1)=8 holds true is _______.IPMAT Indore 2024Let fff and ggg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x||f(x)=∣x+∣x∣∣ and g(x)=1xg(x) = \frac{1}{x}g(x)=x1 for x≠0x \neq 0x=0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6}f(a)+g(f(a))=613 for some real aaa, then the maximum possible value off(g(a)) f(g(a))f(g(a)) is:IPMAT Indore 2023If f(1)=1f(1) = 1f(1)=1 and f(n)=3n−f(n−1)f(n) = 3n - f(n - 1)f(n)=3n−f(n−1) for all integers n>1n > 1n>1 , then the value of f(2023)f(2023)f(2023) is