IPMAT IndoreAlgebra > Hardpositive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2}, +\infty)∈(25+57,+∞)negative and monotonically decreasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)negative and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and positive and monotonically increasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)positive and monotonically increasing for x ∈(−∞,5−572)\in (-\infty, \frac{5-\sqrt{57}}{2})∈(−∞,25−57) and negative and monotonically decreasing for x ∈(5+572,+∞)\in (\frac{5+\sqrt{57}}{2},+\infty)∈(25+57,+∞)✅ Correct Option: 3Related questions:IPMAT Indore 2021Suppose that a real-valued function f(x)f(x)f(x) of real numbers satisfies f(x+xy)=f(x)+f(xyf(x + xy) = f(x) + f(xyf(x+xy)=f(x)+f(xy) for all real x,y,x, y,x,y, and that f(2020)=1f(2020) = 1f(2020)=1. Compute f(2021)f(2021)f(2021).IPMAT Indore 2022If f(x2+f(y))=xf(x)+yf\left(x^{2}+f(y)\right)=x f(x)+yf(x2+f(y))=xf(x)+y for all non-negative integers xxx and yyy, then the value of [f(0)]2+f(0)[f(0)]^{2}+f(0)[f(0)]2+f(0) equals _________.IPMAT Indore 2022Let A={1,2,3}A=\{1,2,3\}A={1,2,3} and B={a,b}B=\{a, b\}B={a,b}. Assuming all relations from set AAA to set BBB are equally likely, what is the probability that a relation from AAA to BBB is also a function?