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If x∈(a,b)x ∈ (a, b) satisfies the inequality x−3x2+3x+2≥1\dfrac{x - 3}{x^2 + 3x + 2} \geq 1, then the largest possible value of b−ab - a is

Solution

✅ Correct Option: 2
Solution figure for IPMAT Indore 2019 MCQ question 7 (Algebra)

*(b−a)max=−1+2=1(b-a)_{max}=-1+2=1

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