IPMAT IndoreModern Math > Mediumf(x)>g(x)>0f(x) > g(x) > 0f(x)>g(x)>0 for 0<a<10 < a < 10<a<1 and g(x)>f(x)>0g(x) > f(x) > 0g(x)>f(x)>0 for a>1a > 1a>1g(x)>f(x)>0g(x) > f(x) > 0g(x)>f(x)>0 for 0<a<10 < a < 10<a<1 and f(x)>g(x)>0f(x) > g(x) > 0f(x)>g(x)>0 for a>1a > 1a>1f(x)>g(x)>0f(x) > g(x) > 0f(x)>g(x)>0 for a>0a > 0a>0g(x)>f(x)>0g(x) > f(x) > 0g(x)>f(x)>0 for a>0a > 0a>0✅ Correct Option: 1Related questions:IPMAT Indore 2019The inequality log23x−12−x<1\log_{2} \frac{3x - 1}{2 - x} < 1log22−x3x−1<1 holds true forIPMAT Indore 2022The set of real values of xxx for which the inequality log278≤log3x<91log23\log _{27} 8 \leq \log _{3} x \lt 9^{\frac{1}{\log _{2} 3}}log278≤log3x<9log231 holds isIPMAT Indore 2025If log3(x2−1)\log_3(x^2 - 1)log3(x2−1), log3(2x2+1)\log_3(2x^2 + 1)log3(2x2+1) and log3(6x2+3)\log_3(6x^2 + 3)log3(6x2+3) are the first three terms of an arithmetic progression, then the sum of the next three terms of the progression is