A boy agrees to work at the rate of one rupee on the first day, two rupees on the second day, four rupees on third day and

so on, thus getting on any day twice the amount he received just the day before. How many rupees will the boy earn in all, if

he started working on the $5^{th}$ of March and completed the work on the $28^{th}$ of March?

What is the sum of the infinite series: $1 - \frac{1}{2} - \frac{1}{4} + \frac{1}{8} - \frac{1}{16} - \frac{1}{32} + \frac{1}{64} - \frac{1}{128} - \frac{1}{256} + \dots?$

The 5th term of an arithmetic sequence is 20 and its 10th term is 35. The first term of a geometric sequence is the same as the first term of the arithmetic sequence mentioned above, while the 4th term of the geometric sequence is 1. What will be the sum to infinity of the arithmetic-geometric sequence whose $n$-th term is given by $[a+(n-1)d]\times r^{n-1}$, where $a$ is the first term of both the arithmetic and the geometric sequences, $d$ is the common difference of the arithmetic sequence, and $r$ is the common ratio of the geometric sequence?

A theatre has 30 rows of seats arranged in such a way that the number of seats in each row forms an arithmetic progression. The first row contains 18 seats, and each successive row has 3 more seats than the previous row. Due to renovation rules, only those rows whose seat count is divisible by 6 are reserved for premium booking. Find the total number of premium seats in the theatre.

If six arithmetic means are inserted between 3 and $\frac{13}{2}$, the ratio of the fifth and the first mean is:

The sum of the first 3 terms of an AP is 6 and that of the last 3 terms is 16. If the AP has 13 terms, what is the Arithmetic mean of the three terms that are exactly at the middle of the progression?

Let $\dfrac{m}{n} = \dfrac{90^2+5 \times 90+4}{90^2+5\times 90+6} \times \dfrac{91^2+5\times 91+4}{91^2+5\times 91+6} \times .......\times \dfrac{98^2+5\times 98+4}{98^2+5\times 98+6}$ where m and n are co-primes.

What is the value of $|m - n|$ ?