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A shopkeeper sold article A at a profit of 18%18\% and article B at a loss of 10%10\%, thus making an overall profit of Rs.8585. If he had sold at article A at an 11%11\% loss and article B at an 8%8\% profit, he would have suffered a loss of Rs.3434. Find the sum (in Rs.) of the cost prices of article A and article B.

Solution

✅ Correct Option: 1

Let cost price of article A =100x100x

Cost price of Article B =100y100y

From the given statements, 18x−10y=8518x-10y=85

8y−11x=−348y-11x = -34

Solving this equations, we get x=10x=10, y=9.5y=9.5

Cost price of article A = 100x100x = Rs.10001000

Cost price of article B = 100y100y = Rs.950950

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