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BBA-DBE Bangalore 2026 PYQsQuantitative Ability. Free, no login required.

A theatre has 30 rows of seats arranged in such a way that the number of seats in each row forms an arithmetic progression. The first row contains 18 seats, and each successive row has 3 more seats than the previous row. Due to renovation rules, only those rows whose seat count is divisible by 6 are reserved for premium booking. Find the total number of premium seats in the theatre.

Solution

✅ Correct Option: 1

The number of seats in row nn is an=18+3(n−1)=3n+15=3(n+5)a_n=18+3(n-1)=3n+15=3(n+5).

This is divisible by 6 when n+5n+5 is even, so nn must be odd.

The premium rows are 1,3,5,…,291,3,5,\ldots,29, giving 15 rows. Their seat counts form an arithmetic progression from 18 to 102.

Total premium seats =152(18+102)=900=\dfrac{15}{2}(18+102)=900.

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