IIM Bangalore (BBA-DBE) - Modern Math - Permutation & Combination | Free Questions

Q1:

IIM Bangalore (BBA-DBE) 2025

Modern Math > Permutation & Combination

Hard

A person hosts a party of 13 guests and places 5 of them on one table and the remaining on the other table, the tables being round. In how many ways can he arrange the guests?

$\frac{13!}{40}$

$\frac{13!}{5!8!}$

$\frac{13!}{4!7!}$

$\frac{13!}{80}$

Correct Answer

Option 1

Correct Answer

Explanation →

Q2:

IIM Bangalore (BBA-DBE) 2024 Slot 2

Modern Math > Permutation & Combination

Medium

Out of 7 different consonants and 4 different vowels, how many words (not necessarily meaningful) of 4 consonants and 2 vowels can be formed?

151200

210

720

142500

Correct Answer

Option 1

Correct Answer

Explanation →

Q3:

IIM Bangalore (BBA-DBE) 2024 Slot 1

Modern Math > Permutation & Combination

Hard

Two British and three Indian men and their wives are to be seated around a circular table. If the seating arrangements are defined only by the relative positions of the people, then the total number of ways in which each British man can be seated next to his wife and each Indian man can also be, simultaneously, seated next to his wife is:

768

790

850

904

Correct Answer

Option 1

Correct Answer

Explanation →

IIM Bangalore (BBA-DBE) Modern Math > Permutation & Combination PYQs

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