Q1:
2025: 30 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
The effective rate equivalent to a nominal rate of 12% compounded quarterly is: (Given )
2025: 30 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
The effective rate equivalent to a nominal rate of 12% compounded quarterly is: (Given )
2025: 30 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
If an investment value get doubled in 10 years then its compound annual growth rate (CAGR) is: (Given )
2025: 30 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
Ramesh plans to save some amount required after 10 years for higher studies of his son. He expects the cost of these studies to be Rs.1,00,000. How much should he save at the beginning of each year to accumulate this amount at the end of 10 years, if the interest rate is 12% compounded annually. (Given )
2025: 30 May Shift 1
Statistics & Applications
Financial Math
Easy
Applied
The scrap value of a machine costing ₹ 75,000 after 4 years of use is ₹ 25000. Using straight line method the annual depreciation of the machine is:
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
A trust invites a deposit of lumpsum amount from individual so that annual scholarship of Rs.5000 is paid. Rate of interest is 5% per annum. If the scholarship is to start at the end of this year then the amount needed to deposit to Trust is:
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Mrs Rathna invested Rs 2 lakh in an enterprise for 5 years. Her compound annual growth rate (CAGR) turned out to be 20.5%. The end balance would be: (given
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
The amount to which ₹ 5000 will accumulate at the effective rate of 4% for 4 years and 5% for 2 years is
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Easy
Applied
Every year the price of a motorcycle depreciates by Rs. 15000. After 12 years its price has become Rs. 50000. Then its original cost was:
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Rakshita plans to buy a house for Rs.1,00,00,000 with down payment of 20% of the value of house paid by her mother, Rest of the amount she wishes to pay in 25 years by equal monthly installment at an interest of 9% per annum compounded monthly. Then the EMI paid by her is: (Given = 9 )
2025: 29 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
A charity organization has a fund of Rs.2,00000 to provide annual grants to students. The grant amount each year is Rs.15,000. The fund earns an interest rate of r% per annum. If the interest earned is used entirely to provide the grants, then the annual interest rate r is:
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
Mr. Jayesh plans to save amount for higher studies of his daughter, required after 10 years. How much amount should he save at the beginning of each year to accumulate Rs.1,00,000 at the end of 10 years. If rate of interest is 12% compounded annually? [Given ]
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
Mohini purchases a house worth Rs. 50 lakhs and makes a down payment of Rs. 11.2 lakhs. She pays the remaining amount on monthly EMI using a reducing balance method. The bank charges 6% per annum compounded monthly for a tenure of 25 years. Her EMI is:
[Given: ]
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
As per the graph given below:
Match List-I with List-II
| List-I | List-II |
|---|---|
| (Function/Area/point) | (Representation) |
| (A) Consumers Surplus | (I) y=g(x) |
| (B) Supply function | (II) v |
| (C) Demand function | (III) s |
| (D) Equilibrium point | (IV) y=f(x) |
Choose the correct answer from the options given below:
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Easy
Applied
If an asset costs Rs. 50,000 with an estimated useful life of 6 years and a scrap value of Rs. 5000. Then by using a linear depreciation method, the annual depreciation of the asset will be:
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
Rs. 2,50,000 cash is equivalent to a perpetuity of Rs.7500 payable at the end of each quarter. Then the rate of interest is
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
Ram had invested Rs. 15,000 in a mutual fund and the value of the investment at the time of redemption was Rs. 25,000. If the compound annual growth rate (CAGR) is 8.88%, then the number of years for which Ram has invested the amount is:
[Given: and ]
2025: 27 May Shift 1
Statistics & Applications
Financial Math
Medium
Applied
A person has set up a sinking fund in order to have Rs. 10,00,000 after 10 years for his child education. The amount should put bi-annually into account paying 5% per annum compounded semi-annually is: [Given ]
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Anisha invested Rs.20000 in a mutual fund in the year 2016, which increased to Rs.36000 in the year 2024. The percentage compounded annual growth rate(CAGR) of her investment is:
(Given: )
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
At what rate will the present value of a perpetuity of Rs.1000 payable at the end of each quarter be Rs.50000?
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Easy
Applied
The annual depreciation of an asset is independent of:-
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
The amount should be deposited at the end of every 6 months to accumulate Rs.50,000 in 8 years if money is worth 6% p.a. compounded semiannually, is: [Given ]
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Vatsala buys a car for Rs.7,00,000 and pays upfront Rs.2,50,000 through her credit card. The balance is to be paid in 5 years by equal monthly installments at an interest of 7% per annum as reducing balance. The EMI to be paid by Vatsala will be :- [given (1.0058)⁻⁶⁰=0.7068]
2025: 26 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
A man wishes to ensure that he gets Rs. 75,000/- at the end of each year indefinitely. The amount that he invest now to produce the desired cash flow, if money is worth 2.5% compounded annually is:
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Ajesh has set up a sinking fund in order to have ₹ 10,00,000 after 10 years for his son's education. The amount should be set aside at the end of every 6 months into an account paying 5% per annum compounded half yearly is: [given ]
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
A machine costing ₹ 36000 has an effective life of 5 years with scrap value of ₹ 5000 following a linear method of depreciation. Which of the following statements are correct?
(A) The value of the machine after 1 year is ₹ 31000
(B) The value of the machine after 2 years is ₹ 23600
(C) The value of the machine after 3 years is ₹ 18400
(D) The value of the machine after 4 years is ₹ 11200
Choose the correct answer from the options given below:
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
At what rate of interest will the present value of a perpetuity of ₹ 500 payable at the end of every 6 months be ₹ 20,000?
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
The declared rate of return compounded semi annually equivalent to the effective rate of return 10.25% per annum is:
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Rahul invested ₹ 20000 in a mutual fund in year 2018. If the value of mutual fund increased to ₹ 32000 in year 2023. Then the compound annual growth rate of his investment is:
2025: 22 May Shift 2
Statistics & Applications
Financial Math
Medium
Applied
Anush takes a loan of ₹ 150000 @ 16% annual interest for 5 years. His EMI (Equally Monthly Installment) on monthly basis under flat rate system is:
2025: 22 May Shift 1
Statistics & Applications
Financial Math
Easy
Applied
A machine costing ₹ 1,00,000 has a useful life of 5 years. The estimated scrap value is ₹ 20,000. Using straight line method the annual depreciation is