CUET Mathematics: CalculusDifferential Equations. Free, no login required.

Q1:

2025: 30 May Shift 2

Differential Equations

Easy

Common

The solution of the differential equation dydx=yx\frac{dy}{dx} = \sqrt\frac{{y}}{x} is

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 1

Q2:

2025: 30 May Shift 2

Differential Equations

Medium

Common

The order of 1+(dydx)2=[ad2ydx2]12\sqrt{1 + \left(\frac{dy}{dx}\right)^2} = \left[a \frac{d^2y}{dx^2}\right]^{\frac{1}{2}} is

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 2

Q3:

2025: 30 May Shift 2

Differential Equations

Medium

Core

The general solution of the differential equation x(dydx)=y+xtan⁡(yx)x\left(\frac{dy}{dx}\right) = y + x \tan\left(\frac{y}{x}\right) is

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 3

Q4:

2025: 30 May Shift 2

Differential Equations

Medium

Core

The sum of order and degree of the differential equation y=xdydx+21+(dydx)2y = x\frac{dy}{dx} + 2\sqrt{1 + \left(\frac{dy}{dx}\right)^2} is

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 4

Q5:

2025: 30 May Shift 1

Differential Equations

Medium

Common

Which of the following are first order linear differential equations?

(A) dxdy+P1(y)x=Q1(y)\frac{dx}{dy} + P_1(y)x = Q_1(y) : P1(y)P_1(y) and Q1(y)Q_1(y) are functions of y or constant functions

(B) dydx+P2(x)y=Q2(x)\frac{dy}{dx} + P_2(x)y = Q_2(x) : P2(x)P_2(x) and Q2(x)Q_2(x) are functions of x or constant functions

(C) (x+y)dydx=x−2y(x + y)\frac{dy}{dx} = x - 2y

(D) (1+x2)dydx−2xy=x2+3(1 + x^2)\frac{dy}{dx} - 2xy = x^2 + 3

Choose the correct answer from the options given below:

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 5

Q6:

2025: 30 May Shift 1

Differential Equations

Medium

Common

The solution of the differential equation log⁡e(dydx)=5x+2y\log_e\left(\frac{dy}{dx}\right) = 5x + 2y is given by

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 6

Q7:

2025: 30 May Shift 1

Differential Equations

Medium

Core

For the differential equation ydx−(x+3y2)dy=0ydx - (x + 3y^2)dy = 0, which of the following statements are true?

(A) It is a linear differential equation

(B) It is a homogenous differential equation

(C) Its general solution is x=3y2+Cyx = 3y^2 + Cy : CC is an arbitrary constant

(D) If y(0)=1y(0) = 1, then its particular solution is x=3y2−1x = 3y^2 - 1

Choose the correct answer from the options given below:

Answer options
Option 1
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 7

Q8:

2025: 30 May Shift 1

Differential Equations

Medium

Core

The product of order and degree of the differential equation (d3ydx3)2+x2y(d2ydx2)3=2x5\left(\frac{d^3y}{dx^3}\right)^2 + x^2y\left(\frac{d^2y}{dx^2}\right)^3 = 2x^5 is:

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 8

Q9:

2025: 30 May Shift 1

Differential Equations

Medium

Applied

The differential equation representing the family of curves y=Ax+Bxy = Ax + \frac{B}{x}, x≠0x \neq 0 where A and B are arbitrary constants, is given by

Answer options
Option 4
Correct Answer
Explanation for 2025: 30 May Shift 1 MAT question 9

Q10:

2025: 29 May Shift 2

Differential Equations

Medium

Common

Match List-I with List-II:

List-IList-II
Differential EquationsDegree/Order
(A) Degree of the differential equation d3ydx3+2log⁡x.y=0\frac{d^3y}{dx^3} + 2 \log x.y = 0(I) 3
(B) Order of the differential equation d4ydx4+(dydx)4+xy=0\frac{d^4y}{dx^4} + \left(\frac{dy}{dx}\right)^4 + xy = 0(II) 2
(C) Degree of the differential equation (d4ydx4)2+(dydx)3+x2y=0\left(\frac{d^4y}{dx^4}\right)^2 + \left(\frac{dy}{dx}\right)^3 + x^2y = 0(III) 1
(D) Order of the differential equation d3ydx3+y(dydx)3=0\frac{d^3y}{dx^3} + y\left(\frac{dy}{dx}\right)^3 = 0(IV) 4
Answer options

Q11:

2025: 29 May Shift 2

Differential Equations

Easy

Common

The particular solution of the differential equation dydx=8yx\frac{dy}{dx} = 8yx when y=1y = 1 at x=0x = 0

Answer options

Q12:

2025: 29 May Shift 2

Differential Equations

Medium

Core

For the differential equation xdydx+3y=x2log⁡exx\frac{dy}{dx} + 3y = x^2\log_e x, which of the following statements are TRUE?

(A) Product of order and degree is 1

(B) Integrating factor is x3x^3

(C) Integrating factor is 3x3x

(D) General solution is y=x336(6log⁡e∣x∣−1)+Cx−3y = \frac{x^3}{36}(6\log_e|x| - 1) + Cx^{-3}, C is an arbitrary constant.

Choose the correct answer from the options given below:

Answer options

Q13:

2025: 29 May Shift 2

Differential Equations

Easy

Core

The number of arbitrary constants in the general solution of a differential equation of order 4 and degree 1 is

Answer options

Q14:

2025: 27 May Shift 1

Differential Equations

Easy

Common

The particular solution of the differential equation dydx+3yx=0\frac{dy}{dx} + \frac{3y}{x} = 0, y(1)=1y(1) = 1 is

Answer options

Q15:

2025: 27 May Shift 1

Differential Equations

Medium

Common

Which one of the following equations is a homogeneous differential equation?

Answer options

Q16:

2025: 27 May Shift 1

Differential Equations

Medium

Core

The solution of the differential equation (x2+xy)dy=(x2+y2)dx(x^2 + xy)dy = (x^2 + y^2)dx is

Answer options

Q17:

2025: 27 May Shift 1

Differential Equations

Medium

Core

Match List-I with List-II

List-IList-II
(A) The degree of the differential equation (d2ydx2)2+(dydx)2=xsin⁡(dydx)\left(\frac{d^2y}{dx^2}\right)^2 + \left(\frac{dy}{dx}\right)^2 = x\sin\left(\frac{dy}{dx}\right)(I) 4
(B) The degree of differential equation d2ydx2+(dydx)1/4+x1/5=0\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^{1/4} + x^{1/5} = 0(II) 1
(C) The degree of differential equation d2ydx2+(dydx)3+6y5=0\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^3 + 6y^5 = 0(III) Not defined
(D) The degree of differential equation 1+(dydx)4=7(d2ydx2)31 + \left(\frac{dy}{dx}\right)^4 = 7\left(\frac{d^2y}{dx^2}\right)^3(IV) 3

Choose the correct answer from the options given below:

Answer options

Q18:

2025: 26 May Shift 2

Differential Equations

Hard

Common

In the following differential equation d2ydx2+(dydx)2=2x2log⁡(d2ydx2)\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 = 2x^2 \log\left(\frac{d^2y}{dx^2}\right) order and degree is:

Answer options

Q19:

2025: 26 May Shift 2

Differential Equations

Easy

Common

The solution of the differential equation xdy−ydx=0xdy - ydx = 0 represents

Answer options

Q20:

2025: 26 May Shift 2

Differential Equations

Medium

Core

The particular solution of the differential equation dydx=ex2/2+xy\frac{dy}{dx} = e^{x^2/2} + xy, when x=0x = 0, y=1y = 1, is

Answer options

Q21:

2025: 26 May Shift 2

Differential Equations

Medium

Core

Match List-I with List-II

List-IList-II
Differential EquationsOrder and degree
(A) ydx+xlog⁡(y/x)dy−2xdy=0ydx + x\log(y/x)dy - 2xdy = 0(I) Order : 2, degree:1
(B) (d3ydx3)2+3d2ydx2+2(dydx)4=y2\left(\frac{d^3y}{dx^3}\right)^2 + 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^2(II) Order :1, degree:1
(C) dydx+log⁡(dydx)+x=y\frac{dy}{dx} + \log\left(\frac{dy}{dx}\right) + x = y(III) Order : 3, degree:2
(D) (dsdt)4+2sd2sdt2=0\left(\frac{ds}{dt}\right)^4 + 2s\frac{d^2s}{dt^2} = 0(IV) Order : 1, degree: Not defined

Choose the correct answer from the options given below:

Answer options

Q22:

2025: 26 May Shift 2

Differential Equations

Medium

Applied

Curd is at 80° F, five minutes later it came down at 60°F. After another 5 minutes, its temperature became 50° F. Given that the rate of change of temperature is proportional to (T - S), where S is temperature of the surroundings and T is temperature of the curd at any time t. Then the temperature of the surroundings is :

Answer options

Q23:

2025: 22 May Shift 2

Differential Equations

Medium

Common

Match List-I with List-II

List-IList-II
Differential EquationOrder and Degree
(A) (d2ydx2)2=ex(dydx)4+1=0\left(\frac{d^2y}{dx^2}\right)^2 = e^x\left(\frac{dy}{dx}\right)^4 + 1 = 0(I) order = 1 and degree = 2
(B) (dydx)2+xy=0\left(\frac{dy}{dx}\right)^2 + xy = 0(II) order = 2 and degree = 1
(C) (1+dydx)3/2=4(d2ydx2)2\left(1 + \frac{dy}{dx}\right)^{3/2} = 4\left(\frac{d^2y}{dx^2}\right)^2(III) order = 2 and degree = 2
(D) d2ydx2+1=dydx\sqrt\frac{d^2y}{dx^2} + 1 = \frac{dy}{dx}(IV) order = 2 and degree = 4

Choose the correct answer from the options given below:

Answer options

Q24:

2025: 22 May Shift 2

Differential Equations

Medium

Common

The solution of the differential equation dydx=(1+x2)(1+y2)\frac{dy}{dx} = (1 + x^2)(1 + y^2) is (Here C is an arbitrary constant)

Answer options

Q25:

2025: 22 May Shift 2

Differential Equations

Medium

Core

The particular solution of the differential equation [xsin⁡2(yx)−y]dx+xdy=0\left[x \sin^2\left(\frac{y}{x}\right) - y\right]dx + xdy = 0, y=π4y = \frac{\pi}{4} when x=1x = 1 is

Answer options

Q26:

2025: 22 May Shift 2

Differential Equations

Medium

Core

Match List-I with List-II

List-IList-II
Differential EquationIntegrating Factor
(A) dydx+2xy=1\frac{dy}{dx} + 2xy = 1(I) xx
(B) xdydx+2xy=1x\frac{dy}{dx} + 2xy = 1(II) e2xe^{2x}
(C) xdydx+y=1x\frac{dy}{dx} + y = 1(III) x2x^2
(D) xdydx+2y=2x\frac{dy}{dx} + 2y = 2(IV) ex2e^{x^2}

Choose the correct answer from the options given below:

Answer options

Q27:

2025: 22 May Shift 1

Differential Equations

Medium

Common

Match List-I with List-II

List-IList-II
Differential EquationDegree
(A) xyd2ydx2+x(dydx)2−ydydx=0xy\frac{d^2y}{dx^2} + x\left(\frac{dy}{dx}\right)^2 - y\frac{dy}{dx} = 0(I) 3
(B) d2ydx2+log⁡(dydx)=0\frac{d^2y}{dx^2} + \log\left(\frac{dy}{dx}\right) = 0(II) 1
(C) (d2ydx2)2+(dydx)3+dydx+1=0\left(\frac{d^2y}{dx^2}\right)^2 + \left(\frac{dy}{dx}\right)^3 + \frac{dy}{dx} + 1 = 0(III) not defined
(D) 2x2(d2ydx2)3−5(dydx)3+y=02x^2\left(\frac{d^2y}{dx^2}\right)^3 - 5\left(\frac{dy}{dx}\right)^3 + y = 0(IV) 2

Choose the correct answer from the options given below:

Answer options

Q28:

2025: 22 May Shift 1

Differential Equations

Medium

Common

The solution of the differential equation drdt=−rt,r(0)=r0\frac{dr}{dt} = -rt, r(0) = r_0 is

Answer options

Q29:

2025: 22 May Shift 1

Differential Equations

Medium

Core

The solution of the differential equation dydx−yx=2log⁡ex\frac{dy}{dx} - \frac{y}{x} = 2\log_e x

Answer options

Q30:

2025: 22 May Shift 1

Differential Equations

Hard

Core

Which of the following statements is/are true?

(A) (tan⁡−1y−x)dy=(1+y2)dx(\tan^{-1} y - x)dy = (1 + y^2)dx is a differential equation where variables are separable.

(B) (1+x2)dy+2xydy=cot⁡x dx(x≠0)(1 + x^2)dy + 2xydy = \cot x \ dx (x \neq 0) is a first order linear differential equation.

(C) (4x+6y+5)dy−(3y+2x+4)dx=0(4x + 6y + 5)dy - (3y + 2x + 4)dx = 0 is not a homogeneous differential equation.

(D) (xy)dx−(x+y2)dy=0(xy)dx - (x + y^2)dy = 0 is a homogeneous differential equation.

Choose the correct answer from the options given below:

Answer options