CUET Mathematics: CalculusDifferential Equations. Free, no login required.

Q1:

2026: 15 May Shift 1

Differential Equations

Medium

Common

The order and degree of differential equation y=px+a2p2+b2,p=dydxy = px + \sqrt{a^2p^2 + b^2}, p = \dfrac{dy}{dx}, aa and bb are constants are:

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Option 4
Correct Answer
Explanation for 2026: 15 May Shift 1 MAT question 1

Q2:

2026: 15 May Shift 1

Differential Equations

Medium

Common

If cc is an arbitrary constant, then

Match the LIST-I with LIST-II

LIST-I (Differential Equation)LIST-II (Solution)
A.dydx=1+x+y+xy\dfrac{dy}{dx} = 1 + x + y + xyI.log⁡e∣y∣=2x+log⁡e(x−1)2+c\log_e \vert y \vert = 2x + \log_e (x-1)^2 + c
B.(x−1)dydx=2xy(x-1)\dfrac{dy}{dx} = 2xyII.y=cxy = cx
C.dydx=1−x+y−xy\dfrac{dy}{dx} = 1 - x + y - xyIII.log⁡e∣1+y∣=x+x22+c\log_e \vert 1+y \vert = x + \dfrac{x^2}{2} + c
D.x dy=y dxx\,dy = y\,dxIV.log⁡e∣1+y∣=x−x22+c\log_e \vert 1+y \vert = x - \dfrac{x^2}{2} + c

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Option 1
Correct Answer
Explanation for 2026: 15 May Shift 1 MAT question 2

Q3:

2026: 15 May Shift 1

Differential Equations

Easy

Core

If pp and qq are degree and order of the differential equation (d2ydx2)3−2(dydx)4=6\left(\dfrac{d^2y}{dx^2}\right)^3 - 2\left(\dfrac{dy}{dx}\right)^4 = 6 respectively. Then the value of 2p+3q2p+3q is

Answer options
Option 2
Correct Answer
Explanation for 2026: 15 May Shift 1 MAT question 3

Q4:

2026: 15 May Shift 1

Differential Equations

Medium

Core

The solution of the differential equation dydx=x2+xy+y2x2\dfrac{dy}{dx} = \dfrac{x^2+xy+y^2}{x^2} for x>0,y>0x>0, y>0 at x=1,y=2x=1, y=2 is

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Option 3
Correct Answer
Explanation for 2026: 15 May Shift 1 MAT question 4

Q5:

2026: 15 May Shift 1

Differential Equations

Easy

Applied

Match the LIST-I with LIST-II

LIST-I (Differential equation)LIST-II (Sum of order and degree)
A.(y′′)3+xy′+2y=0(y'')^3 + xy' + 2y = 0I.66
B.(y′′)2+(y′)3+4y=0(y'')^2 + (y')^3 + 4y = 0II.33
C.y′′+(y′)2+5y=0y'' + (y')^2 + 5y = 0III.44
D.(y′′)4+3x(y′)2+y=0(y'')^4 + 3x(y')^2 + y = 0IV.55

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Option 4
Correct Answer
Explanation for 2026: 15 May Shift 1 MAT question 5

Q6:

2026: 14 May Shift 2

Differential Equations

Easy

Common

The solution of the differential equation dydx=x2+x+1x\frac{dy}{dx} = x^2 + x + \frac{1}{x} is

Answer options
Option 2
Correct Answer
Explanation for 2026: 14 May Shift 2 MAT question 6

Q7:

2026: 14 May Shift 2

Differential Equations

Easy

Common

Particular solution of the differential equation dy+2xy2dx=0dy + 2xy^2 dx = 0, given that y=1y=1, when x=0x=0, is

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Option 3
Correct Answer
Explanation for 2026: 14 May Shift 2 MAT question 7

Q8:

2026: 14 May Shift 2

Differential Equations

Medium

Common

Match the LIST-I with LIST-II

LIST-I (Differential Equation)LIST-II (Order and degree)
A.log⁡(dydx)+d2ydx2=0\log\left(\dfrac{dy}{dx}\right) + \dfrac{d^2y}{dx^2} = 0I.Order : 3 and degree : not defined
B.d3ydx3+y2+edydx=4\dfrac{d^3y}{dx^3} + y^2 + e^{\frac{dy}{dx}} = 4II.Order : 2 and degree : 2
C.ddx(dydx)2+dydx=x\dfrac{d}{dx}\left(\dfrac{dy}{dx}\right)^2 + \dfrac{dy}{dx} = \sqrt{x}III.Order : 2 and degree : not defined
D.(1+(dydx)2)3/2=d2ydx2\left(1+\left(\dfrac{dy}{dx}\right)^2\right)^{3/2} = \dfrac{d^2y}{dx^2}IV.Order : 2 and degree : 1

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Option 1
Correct Answer
Explanation for 2026: 14 May Shift 2 MAT question 8

Q9:

2026: 14 May Shift 2

Differential Equations

Easy

Core

Match the LIST-I with LIST-II

LIST-ILIST-II
A.The degree of the differential equation (d3ydx3)4+(d2ydx2)5+(dydx)+y=0\left(\frac{d^3y}{dx^3}\right)^4+\left(\frac{d^2y}{dx^2}\right)^5+\left(\frac{dy}{dx}\right)+y=0I.0
B.The order of the differential equation (d3ydx3)4+(d2ydx2)5+(dydx)+y2=0\left(\frac{d^3y}{dx^3}\right)^4+\left(\frac{d^2y}{dx^2}\right)^5+\left(\frac{dy}{dx}\right)+y^2=0II.4
C.The number of arbitrary constants in the general solution of a differential equation of second order isIII.3
D.The number of arbitrary constants in a particular solution of a differential equation of third order isIV.2

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Option 2
Correct Answer
Explanation for 2026: 14 May Shift 2 MAT question 9

Q10:

2026: 14 May Shift 2

Differential Equations

Medium

Core

The general solution of the differintial equation : xdydx−ay=1(a≠0)x\frac{dy}{dx}-ay=1(a\neq0) is

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Q11:

2026: 12 May Shift 2

Differential Equations

Medium

Common

Match List-I with List-II

List-I (Differential Equation)List-II (Order and degree)
(A) (d2ydx2)2+edydx=0\left(\dfrac{d^2y}{dx^2}\right)^2 + e^{\frac{dy}{dx}} = 0(I) order = 2, degree = 1
(B) xyd2ydx2+x(dydx)2−ydydx=0xy\dfrac{d^2y}{dx^2} + x\left(\dfrac{dy}{dx}\right)^2 - y\dfrac{dy}{dx} = 0(II) order = 2, degree = not defined
(C) (d3ydx3)2+log⁡e(dydx)=4x\left(\dfrac{d^3y}{dx^3}\right)^2 + \log_e\left(\dfrac{dy}{dx}\right) = 4x(III) order = 3, degree = 2
(D) ddx(d2ydx2)+ydydx=(1+dydx)1/2\dfrac{d}{dx}\left(\dfrac{d^2y}{dx^2}\right) + y\dfrac{dy}{dx} = \left(1+\dfrac{dy}{dx}\right)^{1/2}(IV) order = 3, degree = not defined

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Q12:

2026: 12 May Shift 2

Differential Equations

Medium

Common

The solution of the differential equation dydx=x2y2\dfrac{dy}{dx} = x^2y^2 with y=1y = 1 at x=0x = 0 is

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Q13:

2026: 12 May Shift 2

Differential Equations

Medium

Common

The general solution of the differential equation dydx=1+x+y+xy\dfrac{dy}{dx} = 1+x+y+xy is: (where CC is an arbitrary constant)

(A) 1+y=x+x22+C1+y = x+\dfrac{x^2}{2}+C

(B) log⁡e∣1+y∣2=x2+2x+C\log_e|1+y|^2 = x^2+2x+C

(C) log⁡e∣1−y∣=x−x22+C\log_e|1-y| = x-\dfrac{x^2}{2}+C

(D) log⁡e∣1+y∣=x+x22+C\log_e|1+y| = x+\dfrac{x^2}{2}+C

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Q14:

2026: 12 May Shift 2

Differential Equations

Medium

Core

The general solution of the differential equation ydx+(x−y3)dy=0ydx + (x-y^3)dy = 0 is :

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Q15:

2026: 12 May Shift 2

Differential Equations

Medium

Core

Which of the following differential equations has y=xy=x as one of the particular solution?

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Q16:

2025: 3 June Shift 2

Differential Equations

Medium

Common

The general solution of the differential equation dydx=−4xy2\frac{dy}{dx} = -4xy^2 is given by

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Q17:

2025: 3 June Shift 2

Differential Equations

Medium

Common

Match List-I with List-II

List-IList-II
(A) Degree of this differential equation d4ydx4+2log⁡e(d3ydx3)=0\frac{d^4y}{dx^4} + 2\log_e\left(\frac{d^3y}{dx^3}\right) = 0(I) 1
(B) Order of this differential equation e(dydx)3+3y(d2ydx2)3=0e^{\left(\frac{dy}{dx}\right)^3} + 3y\left(\frac{d^2y}{dx^2}\right)^3 = 0(II) 4
(C) Degree of d4ydx4+(dydx)2=0\frac{d^4y}{dx^4} + \left(\frac{dy}{dx}\right)^2 = 0(III) not defined
(D) Order of the differential equation 2d4ydx4+(d2ydx2)5=02\frac{d^4y}{dx^4} + \left(\frac{d^2y}{dx^2}\right)^5 = 0(IV) 2

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Q18:

2025: 3 June Shift 2

Differential Equations

Medium

Core

For the differential equation xdydx+2y=x2log⁡exx\frac{dy}{dx} + 2y = x^2\log_e x

(A) Integrating factor is 2x2x

(B) Integrating factor is x2x^2

(C) General Solution is y=x216(4log⁡e∣x∣−1)+Cx−2y = \frac{x^2}{16}(4\log_e|x| - 1) + Cx^{-2} Where C is an arbitrary constant.

(D) General Solution is y=x416(4log⁡e∣x∣−1)+Cy = \frac{x^4}{16}(4\log_e|x| - 1) + C Where C is an arbitrary constant.

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Q19:

2025: 3 June Shift 2

Differential Equations

Easy

Core

The number of arbitrary constants in the particular solution of a differential equation of order 4 and degree 3 is

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Q20:

2025: 3 June Shift 2

Differential Equations

Medium

Applied

The sum of the order and degree of the differential equation representing the family of curves y=mx+m4y = mx + m^4, where m is arbitrary constant, is

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Q21:

2025: 3 June Shift 1

Differential Equations

Medium

Common

The particular solution of the differential equation xdy=(2x2+1)dx,x≠0xdy = (2x^2 + 1)dx, x \neq 0, given that y=1y = 1 when x=1x = 1 is:

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Q22:

2025: 3 June Shift 1

Differential Equations

Medium

Common

If m and n are respectively the order and degree of the differential equation (d2ydx2)2+(dydx)3+y=4x(\frac{d^2y}{dx^2})^{2} + (\frac{dy}{dx})^3 + y= 4x, then the value of m+nm + n is:

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Q23:

2025: 3 June Shift 1

Differential Equations

Medium

Core

Consider the differential equation xdy=(y+2x3)dxxdy = (y + 2x^3)dx. Then which of the following are TRUE?

(A) It is a homogeneous differential equation.

(B) Product of the order and degree of the differential equation in one.

(C) Integrating factor is x.

(D) General solution of the differential equation is y=x3+Cxy = x^3 + Cx, where C is an arbitary constant.

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Q24:

2025: 3 June Shift 1

Differential Equations

Medium

Core

The sum of order and degree of the differential equation (x2d2ydx2)3/4=5(dydx)2−3(x^2\frac{d^2y}{dx^2})^{3/4} = 5(\frac{dy}{dx})^2 - 3 is equal to

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Q25:

2025: 3 June Shift 1

Differential Equations

Medium

Applied

Match List-I with List-II

List-IList-II
Differential EquationSum of order and degree
(A) d2ydx2+dydx+3y=sin⁡x\frac{d^2y}{dx^2} + \frac{dy}{dx} + 3y = \sin x(I) 2
(B) dydx=sin⁡(x+y)\frac{dy}{dx} = \sin(x + y)(II) 3
(C) 1+(dydx)2=d2ydx2\sqrt{1 + (\frac{dy}{dx})^2} = \frac{d^2y}{dx^2}(III) 4
(D) x2(d2ydx2)3+y(dydx)4+y5=0x^2(\frac{d^2y}{dx^2})^3 + y(\frac{dy}{dx})^4 + y^5 = 0(IV) 5

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Q26:

2025: 3 June Shift 1

Differential Equations

Medium

Applied

Solution of the differential equation ylog⁡eydx−xdy=0y\log_e y dx - x dy = 0 is (Where c is an arbitrary constant)

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Q27:

2025: 2 June Shift 1

Differential Equations

Medium

Common

The solution of the differential equation ydx+(x−y2)dy=0ydx + (x - y^2)dy = 0 is

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Q28:

2025: 2 June Shift 1

Differential Equations

Medium

Common

Match List-I with List-II

List-IList-II
(A) The degree of differential equation d3ydx3=edxdy\frac{d^3y}{dx^3} = e^{\frac{dx}{dy}}(I) 2
(B) The order of differential equation (dydx)2+d3ydx3=0\left(\frac{dy}{dx}\right)^2 + \frac{d^3y}{dx^3} = 0(II) 4
(C) The sum of order and degree of differential equation ddx(d2ydx2)+(dydx)5=x\frac{d}{dx}\left(\frac{d^2y}{dx^2}\right) + \left(\frac{dy}{dx}\right)^5 = x(III) not defined
(D) The number of arbitrary constants in the general solution of a differential equation of order 2(IV) 3

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Q29:

2025: 2 June Shift 1

Differential Equations

Medium

Core

The solution of the differential equation dydx=x+yx−y\frac{dy}{dx} = \frac{x+y}{x-y} is

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Q30:

2025: 2 June Shift 1

Differential Equations

Medium

Core

The integrating factor of the differential equation dydx=x+xy\frac{dy}{dx} = x + xy is

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