CUET Mathematics: CalculusApplication of Integrals. Free, no login required.

Area (in sq. units) of the region bounded by the curve $y^2 = 4x$, $y$-axis and the line $y = 3$ is

The area of the smaller region bounded by the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ and the straight line $3x + 4y = 12$ is:

Area of the bounded region between the curve $y = |x - 2|$ and the line $y = 2$ is:

The area bounded by $y = 3x + 1$, $x = 0$, $y = 0$ and $x = a$ is 8 Sq.units. Then value of $a$ (where $a > 0$) is

Area (in sq. units) of the region bounded by the curve $y^2 = 4x$, y-axis and the line $y = 3$ is

The area (in sq. units) bounded by the curve $y = \cos x$ and x-axis between $x = 0$ and $x = \frac{3\pi}{2}$ is

The area (in sq. units) of the region bounded by the curve $y = \sqrt{16-x^2}$ and x-axis is

The nearest integral value of the shaded area shown below is:

Area (in sq. units) of the region bounded by curves $y^2 = x$ and $x = 4$ is

The area (in square units) of the region enclosed between the lines $x + y = 2$, $x = 0$, $x = 3$ and $x$-axis is equal to

The area (in square units) bounded by the curve $y = \cos x$ between $x = 0$ and $x = 2\pi$ in first quadrant is equal to:

The area (in square units) of the region bounded by the curve $x^2 = y$ and the straight line $y = 4$ in the first quadrant is equal to

The demand function for a commodity is $p = 35 - 2x - x^2$, then the consumer's surplus at equilibrium price $p_0 = 20$ is

The area (in sq. units) bounded by the parabola $y^2 = 4ax$, its latus rectum and the $x$-axis in the first quadrant is:

Area of region bounded by the curves $x = y^3$, $x = 0$ between $y = -1$ and $y = 2$ is:

The area (in square units) of the region bounded by the curves $3y^2 = ax$, $y = a$, $a > 0$ and $y$-axis is:

The area of the region bounded by the curves $y = x^2 + 2$ and $x$-axis, between $x = 0$ and $x = 3$ in the first quadrant is:

The area of the region bounded by y² = 9x, x = 2, x = 4 and the x-axis in the first quadrant, is

The area enclosed between the graph of y = x³ and the lines x = 0, y = 1, y = 8 is

The area (sq.units) bounded by the curve y = sinx, π ≤ x ≤ 2π and the x-axis is

The area of the region enclosed between the parabola $y = \frac{3x^2}{4}$ and the line $3x - 2y = 12$ is,

The area bounded by the curve $y = \log x, y = 0$ and $x = e$, is

The area of the region bounded by $y = -1$, $y = 2$, $x = y^3$ and $x = 0$ is $\frac{m}{n}$ sq. units, where $\gcd(m, n) = 1$, then $m - n$ is equal to:

The area of the region bounded by parabola $x^2 = 4y$, straight line $x = 2$ and $x$-axis, is

The area bounded by the curve $y = 4 + 3x - x^2$ and $x$-axis is equal to

The area (in sq. units) bounded by the parabola $y^2 = 16x$ and its latus rectum is

The area of the region (in square units) bounded by $x=1, x=2$ and the curve $y^2 = 4x$ in the first quadrant is

Consider the region bounded by the lines $y - 1 = x, x = -2, x = 3$ and $x$ - axis. Then

(A) The area of the bounded region is given by $\int_{-2}^{3}(x + 1)dx$

(B) The numerical value of the area is $\frac{15}{2}$ sq. units

(C) The numerical value of the area is 8 sq. units

(D) The numerical value of the area is $\frac{17}{2}$ sq. units

Choose the correct answer from the options given below:

Area of the region bounded by the curve $y^2 = 4x$, $y$-axis and the line $y = 3$ is equal to

The area (in sq. units) of the region bounded by the parabola $y^2 = 4x$ and the line $x = 1$ is