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Q1:

2025: 21 May Shift 2

Relations & Functions

Medium

Core

A relation f:N→Nf: N \rightarrow N be defined by f(x)=x2f(x) = x^2, x∈Nx \in N (Set of Natural numbers). Then f(x)f(x) is

Answer options
Option 2
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 1

Q2:

2025: 21 May Shift 2

Relations & Functions

Medium

Core

Let R={(L1,L2):L1⊥L2 R = \{(L_1, L_2): L_1 \perp L_2\ where L1,L2∈LL_1, L_2 \in L (set of straight line in a plane)}, then

Answer options
Option 2
Correct Answer
Explanation for 2025: 21 May Shift 2 MAT question 2

Q3:

2025: 21 May Shift 1

Relations & Functions

Medium

Core

If R be a relation on the set of integers Z, given by R = {(a, b) : (a - b) is a multiple of 3}, then R is:

Answer options
Option 4
Correct Answer
Explanation for 2025: 21 May Shift 1 MAT question 3

Q4:

2025: 21 May Shift 1

Relations & Functions

Medium

Core

Let N be set of natural numbers, then the function f:N→Nf: \mathbb{N} \rightarrow \mathbb{N}, defined by

f(x)={n+12, if n is oddn2, if n is evenf(x) = \begin{cases} \frac{n+1}{2} & \text{, if } n \text{ is odd} \\ \frac{n}{2} & \text{, if } n \text{ is even} \end{cases}, is

Answer options
Option 2
Correct Answer
Explanation for 2025: 21 May Shift 1 MAT question 4

Q5:

2025: 19 May Shift 1

Relations & Functions

Medium

Core

A function f:R→{x∈R:−1<x<1}f: \mathbb{R} \rightarrow \{x \in \mathbb{R}: -1 < x < 1\} is defined as f(x)=x1+∣x∣f(x) = \frac{x}{1+|x|}, then ff is:

Answer options
Option 4
Correct Answer
Explanation for 2025: 19 May Shift 1 MAT question 5

Q6:

2025: 19 May Shift 1

Relations & Functions

Medium

Core

The relation R in R\mathbb{R} (set of real numbers) is defined by R={(a,b):a≤b3}R = \{(a,b): a \leq b^3\}, then R is

Answer options
Option 4
Correct Answer
Explanation for 2025: 19 May Shift 1 MAT question 6

Q7:

2025: 16 May Shift 1

Relations & Functions

Medium

Core

Match List-I with List-II

Where ℝ is set of real numbers

List-IList-II
(A) f: ℝ → ℝ s.t f(x) = x⁴ is(I) one-one, Into
(B) f: ℝ → [0, ∞) s.t f(x) = x⁴ is(II) many-one, into
(C) f: [0, ∞) → ℝ s.t f(x) = x⁴ is(III) one-one, onto
(D) f: [0, ∞) → [0, ∞) s.t f(x) = x⁴ is(IV) many-one, onto

Choose the correct answer from the options given below:

Answer options
Option 2
Correct Answer
Explanation for 2025: 16 May Shift 1 MAT question 7

Q8:

2025: 16 May Shift 1

Relations & Functions

Medium

Core

If R and S are two equivalence relations on a set A, then

Answer options
Option 3
Correct Answer
Explanation for 2025: 16 May Shift 1 MAT question 8

Q9:

2025: 16 May Shift 1

Relations & Functions

Medium

Applied

Which of the following are correct?

(A) If a ≡ b(mod n), then -a ≡ -b (mod n)

(B) If a + b = c, then a(mod n) + b(mod n) ≡ (a + b + c)(mod n).

(C) If a ≡ b (mod n), then ka ≡ kb(mod n), ∀ k ∈ I.

(D) If a ≡ b (mod n), then (a + k) ≡ (b + k)(mod n), ∀ k ∈ I.

Choose the correct answer from the options given below:

Answer options
Option 3
Correct Answer
Explanation for 2025: 16 May Shift 1 MAT question 9

Q11:

2025: 15 May Shift 2

Relations & Functions

Medium

Core

If A={1,2,3,4,...,n}A = \{1, 2, 3, 4, ..., n\} and B={x,y}B = \{x, y\}, then the number of surjections from A to B is

Answer options

Q12:

2025: 15 May Shift 2

Relations & Functions

Medium

Core

A relation R in the set A = {1, 2,3, 4} is given by R = {(1,1), (2,2), (1,2), (2,3), (3,4), (4,4), (1,3), (2,4), (1,4)} is

Answer options

Q13:

2025: 15 May Shift 1

Relations & Functions

Medium

Core

Which of the following functions from Z\mathbb{Z} to Z\mathbb{Z} is a bijective function? (where Z\mathbb{Z} is set of integers)

Answer options

Q14:

2025: 15 May Shift 1

Relations & Functions

Medium

Core

Let A= {1, 2, 3}, then the possible equivalence relations on A are:

(A) {(1, 1), (2, 2) , (3, 3)}

(B) {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)}

(C) {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (1, 3)}

(D) {(1, 1), (2, 2), (3, 3), (1, 3), (3, 1)}

Choose the correct answer from the options given below:

Answer options

Q15:

2025: 14 May Shift 2

Relations & Functions

Medium

Core

Let a relation R = {(a, b) : a is a factor of b, a, b ∈\in N}. Then, R is ______.

Answer options

Q16:

2025: 14 May Shift 2

Relations & Functions

Medium

Core

The function f:[0,∞)→Rf: [0, \infty) \rightarrow \mathbb{R} defined by, f(x)=2x2+3f(x) = 2x^2 + 3, is

Answer options

Q17:

2025: 14 May Shift 1

Relations & Functions

Medium

Core

Let f: R→R\mathbb{R} \rightarrow \mathbb{R} be defined as f(x)=10xf(x) = 10x. Then (Where R\mathbb{R} is the set of real numbers)

Answer options

Q18:

2025: 14 May Shift 1

Relations & Functions

Medium

Core

Let A={1,2,3}A = \{1, 2, 3\}. Then, the number of relations containing (1,2)(1, 2) and (1,3)(1, 3) which are reflexive and symmetric but not transitive, is

Answer options

Q19:

2025: 13 May Shift 2

Relations & Functions

Medium

Core

Match List-I with List-II

Let f:A→Bf: A \rightarrow B be a function given by f(x)=x2f(x) = x^2

List-IList-II
Domain and Co-domainKind
(A) A=RA = \mathbb{R} and B=RB = \mathbb{R}(I) ff is both one-one and onto
(B) A=RA = \mathbb{R} and B=[0,∞]B = [0, \infty](II) ff is one-one but not onto
(C) A=B=[0,∞]A = B = [0, \infty](III) ff is not one-one but onto
(D) A=[0,∞]A = [0, \infty] and B=RB = \mathbb{R}(IV) ff is neither one-one nor onto

Choose the correct answer from the options given below:

Answer options

Q20:

2025: 13 May Shift 2

Relations & Functions

Medium

Core

Let L be the set of all lines in a plane and R be the relation on set L defined by R={(L1,L2):L1⊥L2}R = \{(L_1, L_2): L_1 \perp L_2\} Then R is

(A) an equivalence Relation

(B) a symmetric Relation

(C) not a transitive Relation

(D) a reflexive Relation

Choose the correct answer from the options given below:

Answer options

Q21:

2025: 13 May Shift 1

Relations & Functions

Easy

Core

Let f:Rf: \mathbb{R} -> R\mathbb{R} be a function defined as f(x)=x4f(x) = x^4. Which one of the following is true?

Answer options

Q22:

2025: 13 May Shift 1

Relations & Functions

Medium

Core

Let A={a,b,c}A = \{a, b, c\}. Then number of relations containing (a,b)(a,b) and (b,c)(b, c) which are reflexive and transitive but not symmetric is

Answer options

Q23:

2024: 16 May Shift 1

Relations & Functions

Medium

Core

If the function f:N→Nf: \mathbb{N} \rightarrow \mathbb{N} is defined as f(n)={n−1, if n is even n+1, if n is odd f(n)=\left\{\begin{array}{ll}n-1, & \text { if } n \text { is even } \\ n+1, & \text { if } n \text { is odd }\end{array}\right., then

(A) f is injective

(B) f is into

(C) f is surjective

(D) f is invertible

Answer options

Q24:

2024: 16 May Shift 1

Relations & Functions

Easy

Core

Let R be the relation over the set A of all straight lines in a plane such that l1Rl2⇔l1l_{1} \mathrm{R} l_{2} \Leftrightarrow l_{1} is parallel to l2l_{2}. Then R is :

Answer options

Q26:

2023: 23 May Shift 3

Relations & Functions

Medium

Core

The relation R={(a,b):a≤b2}R = \{(a, b) : a \leq b^2\} on the set of real numbers is:

Answer options

Q27:

2023: 23 May Shift 3

Relations & Functions

Easy

Core

Let f(x)=x3f(x) = x^3 be a function with domain {0, 1, 2, 3} then domain of f−1f^{-1} is :

Answer options

Q28:

2023: 22 May Shift 3

Relations & Functions

Medium

Core

Match List - I with List - II.

List - IList - II
(A)f(x)=1x,f:R−{0}→R−{0}f(x) = \frac{1}{x}, f : \mathbf{R} - \{0\} \to \mathbf{R} - \{0\}(I)neither injective nor surjective
(B)f(x)=x2,f:N→Nf(x) = x^2, f : \mathbf{N} \to \mathbf{N}(II)surjective but not injective
(C)f(x)=x2,f:R→Rf(x) = x^2, f : \mathbf{R} \to \mathbf{R}(III)injective but not surjective
(D)f:{1,2,3}→{1,2}f : \{1, 2, 3\} \to \{1, 2\} defined as f:{(1,1),(2,2),(3,1)}f : \{(1, 1), (2, 2), (3, 1)\}(IV)injective and surjective

Choose the correct answer from the options given below :

Answer options

Q29:

2023: 22 May Shift 3

Relations & Functions

Easy

Core

Let R be a relation on the set of natural numbers N defined by nRm if n divides m. Then R is :

(A) Reflexive Relation

(B) Symmetric Relation

(C) Transitive Relation

(D) Identity Relation

Choose the correct answer from the options given below :

Answer options

Q30:

2023: 22 May Shift 3

Relations & Functions

Easy

Core

If f(x)=xf(x) = \sqrt{x}, g(x)=2x−3g(x) = 2x - 3, then domain of fog(x)fog(x) is :

Answer options