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Q1:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Common

If A=[111102x11]A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 0 & 2 \\ x & 1 & 1 \end{bmatrix} and A−1=14[−20y5−2−112−1]A^{-1} = \frac{1}{4}\begin{bmatrix} -2 & 0 & y \\ 5 & -2 & -1 \\ 1 & 2 & -1 \end{bmatrix}, then values of x and y, are:

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 1

Q2:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Common

Let the matrix A=[aij]3×3A = [a_{ij}]_{3\times3} be defined by

aij={2i+3j,i<j5,i=j3i−2j,i>ja_{ij} = \begin{cases} 2i + 3j, & i < j \\ 5, & i = j \\ 3i - 2j, & i > j \end{cases}

The number of elements in the matrix A which are greater than 7, is:

Answer options
Option 2
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 2

Q3:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

The values of λ\lambda for which the system of equation x+2y+z=14,−x+y+z=10,x+λy+z=2x + 2y + z = 14, - x + y + z = 10, x + \lambda y + z = 2 has unique solution is

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 3

Q4:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

If A and B are two invertible matrices, then which of the following statements are correct?

(A) ∣A−1∣=∣A∣−1|A^{-1}| = |A|^{-1}

(B) adjA=∣A∣A−1adjA = |A|A^{-1}

(C) (AB)−1=A−1B−1(AB)^{-1} = A^{-1}B^{-1}

(D) (A+B)−1=A−1+B−1(A + B)^{-1} = A^{-1} + B^{-1}

Choose the correct answer from the options given below:

Answer options
Option 2
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 4

Q5:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

If ∣x84x∣=∣62186∣\left|\begin{matrix} x & 8 \\ 4 & x \end{matrix}\right| = \left|\begin{matrix} 6 & 2 \\ 18 & 6 \end{matrix}\right|, then xx is/are equal to

Answer options
Option 1
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 5

Q6:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

If A is a square matrix of order 3×33 \times 3 and ∣A∣=4|A| = 4. The value of ∣(adjA).A∣|(adjA).A| is

Answer options
Option 3
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 6

Q7:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

If A=[x−343y−5−4z0]A = \begin{bmatrix} x & -3 & 4 \\ 3 & y & -5\\-4&z&0 \end{bmatrix} is a Skew-Symmetric matrix and adj A=[aij]3×3adj \ A = [a_{ij}]_{3 \times3}, then a11+a22+a33a_{11} + a_{22} + a_{33} is equal to

Answer options
Option 3
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 7

Q8:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Core

If A=[2−34−35x430]A = \begin{bmatrix} 2 & -3 & 4 \\ -3 & 5 & x \\ 4 & 3 & 0 \end{bmatrix} is a symmetric matrix and B=[02−10−2z6y−60]B = \begin{bmatrix} 0 & 2 & -10 \\ -2 & z & 6 \\ y & -6 & 0 \end{bmatrix} is a skew-symmetric matrix, then the value of (xy+yz+zx)(xy + yz + zx) is

Answer options
Option 2
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 8

Q9:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Applied

If the matrix [014x −10−525y]\begin{bmatrix} 0 & 1 & 4x\ \\ -1 & 0 & -5 \\ 2 & 5 & y \end{bmatrix} is skew-symmetric, then

Answer options
Option 2
Correct Answer
Explanation for 2025: 14 May Shift 2 MAT question 9

Q10:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Applied

If A=[4521]A = \begin{bmatrix} 4 & 5 \\ 2 & 1 \end{bmatrix} and II is an identity matrix of order 2, then A−3IA - 3I equals

Answer options

Q11:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Applied

For the system of equations AX = B, which of the following is correct?

Answer options

Q13:

2025: 14 May Shift 2

Matrices & Determinants

Medium

Applied

If A is a square matrix of order 3 such that ∣A∣=3|A| = 3, then ∣adj(adjA)∣|adj(adj A)| is equal to:

Answer options

Q14:

2025: 14 May Shift 1

Matrices & Determinants

Easy

Common

If A=[100−1]A = \begin{bmatrix} 1 & 0 \\ 0 & -1 \end{bmatrix} and B=[0110]B = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} then the matrix AB is equal to

Answer options

Q15:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Common

If A is a square matrix and I is the identity matrix of same order such that A2=IA^2 = I, then (A−I)3+(A+I)3−3A(A - I)^3 + (A + I)^3 - 3A is equal to

Answer options

Q16:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Common

If A=[003030300]A = \begin{bmatrix} 0 & 0 & \sqrt{3} \\ 0 & \sqrt{3} & 0 \\ \sqrt{3} & 0 & 0 \end{bmatrix}, then ∣adjA∣|adj A| is equal to

Answer options

Q17:

2025: 14 May Shift 1

Matrices & Determinants

Easy

Common

Let A = [aij]n×n[a_{ij}]_{n \times n} be a matrix. Then

Match List-I with List-II

List-IList-II
(A) AT=AA^T = A(I) A is a singular matrix
(B) AT=−AA^T = -A(II) A is a non-singular matrix
(C) ∣A∣=0\vert A\vert = 0(III) A is a skew symmetric matrix
(D) ∣A∣≠0\vert A\vert \neq 0(IV) A is a symmetric matrix

Choose the correct answer from the options given below:

Answer options

Q18:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

If A and B are invertible matrices then which of the following statement is NOT correct?

Answer options

Q19:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

Let AX=BAX = B be a system of three linear equations in three variables. Then the system has

(A) a unique solutions if ∣A∣=0|A| = 0

(B) a unique solutions if ∣A∣≠0|A| \neq 0

(C) no solutions if ∣A∣=0|A| = 0 and (adj A) B≠0B \neq 0

(D) infinitely many solutions if ∣A∣=0|A| = 0 and (adj A)B=0B = 0

Choose the correct answer from the options given below:

Answer options

Q20:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

Let A=[cos⁡θ−sin⁡θsin⁡θcos⁡θ]A = \begin{bmatrix} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix} and I=[1001]I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}. If AT+A=IA^T + A = I, then

Answer options

Q21:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

If A and B are skew-symmetric matrices, then which one of the following is NOT true?

Answer options

Q22:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

Let A=[aij]2×3A = [a_{ij}]_{2 \times 3} and B=[bij]3×2B = [b_{ij}]_{3 \times 2}, then ∣5AB∣|5AB| is equal to

Answer options

Q23:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Core

Let A=[121−132241]A = \begin{bmatrix} 1 & 2 & 1 \\ -1 & 3 & 2 \\ 2&4&1\end{bmatrix} and MijM_{ij}, AijA_{ij} respectively denote the minor, co-factor of an element aija_{ij} of matrix A, then which of the following are true?

(A) M22=−1M_{22} = -1

(B) A23=0A_{23} = 0

(C) A32=3A_{32} = 3

(D) M23=1M_{23} = 1

(E) M32=−3M_{32} = -3

Choose the correct answer from the options given below:

Answer options

Q24:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Applied

Which of the following statements is incorrect?

Answer options

Q25:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Applied

Match List-I with List-II

List-IList-II
(Matrix)(Inverse of the Matrix)
(A) (174−2)\begin{pmatrix} 1 & 7 \\ 4 & -2 \end{pmatrix}(I) (2/151/10−1/151/5)\begin{pmatrix} 2/15 & 1/10 \\ -1/15 & 1/5 \end{pmatrix}
(B) (6−324)\begin{pmatrix} 6 & -3 \\ 2 & 4 \end{pmatrix}(II) (1/5−2/15−1/107/30)\begin{pmatrix} 1/5 & -2/15 \\ -1/10 & 7/30 \end{pmatrix}
(C) (52−54)\begin{pmatrix} 5 & 2 \\ -5 & 4 \end{pmatrix}(III) (1/157/302/15−1/30)\begin{pmatrix} 1/15 & 7/30 \\ 2/15 & -1/30 \end{pmatrix}
(D) (7436)\begin{pmatrix} 7 & 4 \\ 3 & 6 \end{pmatrix}(IV) (2/15−1/151/61/6)\begin{pmatrix} 2/15 & -1/15 \\ 1/6 & 1/6 \end{pmatrix}

Choose the correct answer from the options given below:

Answer options

Q26:

2025: 14 May Shift 1

Matrices & Determinants

Medium

Applied

Let A be a non-singular matrix of order 3 and ∣A∣=15|A| = 15, then ∣adjA∣|adj A| is equal to

Answer options

Q27:

2025: 14 May Shift 1

Matrices & Determinants

Easy

Applied

If A=[374−2]A = \begin{bmatrix} 3 & 7 \\ 4 & -2 \end{bmatrix}, X=[α−2]X = \begin{bmatrix} \alpha \\ -2 \end{bmatrix}, B=[732]B = \begin{bmatrix} 7 \\ 32 \end{bmatrix} and AX=BAX = B, then the value of the α\alpha is

Answer options

Q28:

2025: 14 May Shift 1

Matrices & Determinants

Hard

Applied

If PP, QQ and RR are three singular matrices given by P=[23a43]P = \begin{bmatrix} 2 & 3a \\ 4 & 3 \end{bmatrix}, Q=[b52a6]Q = \begin{bmatrix} b & 5 \\ 2a & 6 \end{bmatrix} and R=[a2+b2−c1−cc+1c]R = \begin{bmatrix} a^2 + b^2 - c & 1 - c \\ c + 1 & c \end{bmatrix}, then the value of (2a+6b+17c)(2a + 6b + 17c) is

Answer options

Q29:

2025: 13 May Shift 2

Matrices & Determinants

Medium

Common

If A=[a4−5db−65ec]A = \begin{bmatrix} a & 4 & -5 \\ d & b & -6 \\ 5 & e & c \end{bmatrix} is a skew symmetric matrix, then value of a+b+c+d+ea + b + c + d + e is equal to

Answer options

Q30:

2025: 13 May Shift 2

Matrices & Determinants

Medium

Common

If A=[121231001]A = \begin{bmatrix} 1 & 2 & 1 \\ 2 & 3 & 1 \\ 0 & 0 & 1 \end{bmatrix} then ∣adj(3AT)∣2|adj(3A^T)|^2 is equal to

Answer options